Answer:
K₂S(s) → 2K⁺(aq) + S²⁻(aq)
Explanation:
A strong electrolyte is a compound that, in solution, dissociates completely. For a compound XₐYₙ that dissolves in water:
XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)
Now, potassium sulfide (K₂S), as a strong electrolyte dissolves in water thus:
<em>K₂S(s) → 2K⁺(aq) + S²⁻(aq)</em>
<em></em>
I hope it helps!
In BaF₂ the solubility will decreases on adding NaF
the solubility will increases on adding HCl
<h3>SOLUBILITY OF BARIUM FLUORIDE</h3>
- Increase in temperature will increase the solubility of the solid.
- By adding NaF - decrease the solubility of BaF₂
- By adding HCl - increase the solubility of BaF₂
<h3>BARIUM FLUORIDE</h3>
- It is colourless solid that occur as rare mineral
- It is corroded by moisture
- It is used in window of IR spectroscopy
Hence the barium fluoride the solubility decreases on adding NaF and increases on adding HCl.
Learn more about the solubility on
brainly.com/question/6841847
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Answer: .150 moles of Ana
Explanation:
You just multiply 3.45 g of Na times the number of mole so in this case 1 mole divided by the grams it takes to make that mole. Which can be found on your periodic table it is the number right under the symbol of the element.
Answer:
hydrogen bubbles rise to the surface of the electrolyte and escape into the air, some remain on the surface of the anode. If enough bubbles remain around the anode, the bubbles form a barrier that increases internal resistance.
