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3 years ago

WILL MARK AS BRAINLIEST IF CORRECT

Chemistry

1 answer:

ycow [4]3 years ago

6 0

$\huge\bold{\purple{\bold{⚡Q16. B⚡}}}$

Because: The balanced equation is - 2BrF5--->Br2+5F2

$\huge\bold{\orange{\bold{⚡Q17.A,C,E⚡}}}$

A because 2 is in subscript
Not B because there are 3 atoms of oxygen in ozone, not in oxygen.
C because 3 indeed is its coefficient
Not D because 3 is coefficient not subscript
E is true
Not F because 3 is a coefficient, not 2

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The prophet Isaac was chosen to lead the Israelites after the death of Abraham.

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3 years ago

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For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

To calculate the $E^o_{(Cu^{2+}/Cu)}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}$

Putting values in above equation, we get:

$1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)$

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3 years ago

HELP!!!!!

faltersainse [42]

Answer:

5.17.

Explanation:

[OH⁻] = 1.5 x 10⁻⁹ M.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(1.5 x 10⁻⁹ M) = 6.66 × 10⁻⁶ M.

∵ pH = - log[H₃O⁺]

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3 years ago

How many atoms of Na are in 1.89 mol of Na?

atroni [7]

Answer:

1.138158E24 atoms or 1.14 x 10^24 atoms

Explanation:

To find atoms/particles from moles you just want to convert using avogadro's number which is 6.022 x 10^23

1.89 mol x 6.022 • 10^23

———— = 1.138158E24 atoms

1 mol

so 1.138158E24 atoms or 1.14 x 10^24 for scientific notation

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