The volume of 0.555M KNO3 solution would contain 12.5 g of solute iss 223 mL.
<h3>What is the relationship between mass of solute and concentration of solution?</h3>
The mass of solute in a given volume of solution is related by the formula below:
- Molarity = mass/(molar mass * volume)
Therefore, volume of solution is given by:
Volume = Mass /molarity * molar mass
Molar mass of KNO₃ = 101 g/mol
Volume = 12.5/(0.555 * 101)
Volume = 0.223 L or 223 mL
In conclusion, the volume of the solution is obtained from the molarity of solution as well as mass and molar mass of solute.
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Answer:
A typical organic molecule that contains carbon hydrogen oxygen nitrogen and sulfur will be an amino acid.
Explanation:
Amino acid is the basic protein unit composed of the amino group, carboxylic group, and an alkyl group (which is specific for every amino acid). The R group or alkyl group is what gives the amino acid its identity. For example, the amino acid will be glycine if a Hydrogen atom is attached in place of the R group, and alanine if somehow the R group is replaced by a methyl group. Cystine is a typical example of an amino acid in which carbon, hydrogen oxygen, nitrogen, and sulfur are present. The structure of cystine is given below.
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Answer:
Answered
Explanation:
1)False, electron carriers are not located at ribosomes.
2) True, ATP is the common intermediate between catabolic and anabolic pathways.
3)False, ATP is used for the long-term storage of energy and so is often not found in storage granules.
4) True, Anaerobic organisms are capable of generating ATP via respiration.
5) True , ATP can be generated by the flow of protons across protein channels.
Nucleus
Dna
Rna
Cell membrane
Mitochondria
Vacuoles
Matter
Nuclear membrane
Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %
