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Tems11 [23]
3 years ago
4

The brackets used to express concentration [ ], when making equilibrium constant calculations, indicate_____.

Chemistry
2 answers:
UkoKoshka [18]3 years ago
7 0
The brackets are used to express concentration in moles per liter. The correct option is C.<span />
Fed [463]3 years ago
3 0
Moles per liter

The units of concentration are "molar" and 1 molar solution is one mole per liter.
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Compare chemical equations to math equations.
Valentin [98]

Answer:

They both have letters and different formulas to find the answer.

Explanation:

7 0
3 years ago
Which of the following is NOT the property of a non-metal? A. Non-rigid structure B. Not ductile C. Low density D. Malleable
Vedmedyk [2.9K]

Answer:

The answer is D.

Explanation:

Malleable is the property of <u>m</u><u>e</u><u>t</u><u>a</u><u>l</u> not non-metal.

4 0
4 years ago
Read 2 more answers
Tetrahydrofuran (THF) is a common organic solvent with a boiling point of 339 K. Calculate the total energy (q) required to conv
poizon [28]

Explanation:

For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.

             Q_{1} = mC_{1} \Delta T_{1}

Putting the given values into the above equation as follows.

           Q_{1} = mC_{1} \Delta T_{1}

                      = 27.3 g \times 1.70 J/g K \times 41

                      = 1902.81 J

Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.

           Q_{2} = energy required = mL_{v}

    L_{v} = latent heat of vaporization

Therefor, calculate the value of energy required as follows.

             Q_{2} = mL_{v}

                         = 27.3 \times 444

                         = 12121.2 J

Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.

            Q_{3} = mC_{2} \Delta T_{2}

Value of C_{2} = 1.06 J/g,    \Delta T_{2} = (373 -339) K = 34 K

Hence, putting the given values into the above formula as follows.

             Q_{3} = mC_{2} \Delta T_{2}

                       = 27.3 g \times 1.06 J/g \times 34 K

                       = 983.892 J

Therefore, net heat required will be calculated as follows.

            Q = Q_{1} + Q_{2} + Q_{3}

                = 1902.81 J + 12121.2 J + 983.892 J

                = 15007.902 J

Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.

5 0
3 years ago
How many grams are in 1.6 moles of potassium bromide?​
slava [35]

Answer:

190.4g

Explanation:

1.6mol of KBr (119.002g KBr/1 mol) = 190.4g

since you want to find grams, take the molar mass of KBr (119.002) per 1 mol and use it as your conversion factor (119.002g KBr/1 mol) which will then cancel out mols and leave you with grams.

6 0
4 years ago
Any GUY wanna talk im bore.d
harina [27]

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ⁿᵘ ᵗʰˣ ⁱᵐ ᵃ ᵍᵘʳˡ -.-

6 0
3 years ago
Read 2 more answers
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