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Rudiy27
3 years ago
11

Applying the properties of operations, what is the value of the expression?

Mathematics
2 answers:
Sliva [168]3 years ago
6 0

Answer:

What expression are we supposed to be answering this for?

bagirrra123 [75]3 years ago
6 0

Answer:

i think it is 3.875

Step-by-step explanation:

i'm so sorry if it's incorrect; good luck anyways :)

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Evaluate the expression when x= -3.<br> x² – 7x+6
aksik [14]

Answer:

-6

Step-by-step explanation:

3^{2} = -3 × -3

-3 × -3 =  9

7 × -3 =-21

9 - 21 +6 = -6

7 0
3 years ago
Read 2 more answers
Cheryl spends 3/10 of her savings on a book and 2/5 of it on a pen. What fraction of her savings does Cheryl spend.
Musya8 [376]
7/10 is the answer k
5 0
3 years ago
Read 2 more answers
Help needed!
Jet001 [13]

Answer:

  • 15 inches

Step-by-step explanation:

<u>The ratio of sides in 30º-60º-90º triangle is:</u>

  • a : b : c = 1 : √3 : 2

<u>If a is 5√3, the length of b is:</u>

  • b = a√3 = 5√3 *√3 = 5*3 = 15
7 0
2 years ago
*I WILL MARK YOU BRAINLIEST!!!!!*
AlekseyPX
<h2><em> </em><em>Answer:</em></h2>

<em>-</em><em>3</em>

<em>Explanation</em><em>:</em>

<em>Rate </em><em>of </em><em>change </em><em>in </em><em>the </em><em>interval</em>

<em>X=</em><em>0</em><em> </em><em>to </em><em>X=</em><em>3</em><em> </em><em>is </em><em>given </em><em>by,</em>

<em>r =  \frac{f(3) - f(0)}{3 - 0}  \\ here \\ f(3) = 1 \\ f(0) = 10 \\ r =  \frac{1 - 10}{3}  \\  \:  \:  \:  =  \frac{ - 9}{  3}  \\  \:  \:  \:  \:  =  - 3 \\ hope \: it \: helps.....</em>

4 0
3 years ago
Please help this hurts
Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 \neq 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 \neq 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 \neq 13

The only one that fits is #2.  Let's try the other point to be sure.

2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13

3 0
3 years ago
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