IF YOU ANSWER THESE 2 QUESTIONS! I WILL GIVE YOU BRAINEST!!! 15 POINTS!!!

Steve tunes an old-fashioned radio that has an antenna made from a 3.0-cm-long solenoid with a cross-sectional area of 0.50 cm2

sukhopar [10]

Answer:

$L = 1.88\times10^-^4 H$

Explanation:

It is given that,

Length of the coil, l = 3 cm = 0.03 m

Area of cross section of the coil, $A=0.5\ cm^2=0.00005\ m^2$

Number of turns in the coil, N = 300

inductance of the coil is

$L=\dfrac{\mu_oN^2A}{l}$

$L=\dfrac{4\pi\times 10^{-7}\times (300)^2\times 5\times 10^{-5}}{0.03}\\L = 1.88\times10^-^4 H$

So, the inductance of the coil is 1.88× 10⁻⁴H

5 0

3 years ago

Which statement will be true if you increase the frequency of a periodic wave?

-BARSIC- [3]

"The number of waves per second will increase" is the statement among the choices given in the question that <span>will be true if you increase the frequency of a periodic wave. The correct option among all the options that are given in the question is the first option or option "A". I hope that the answer has helped you.</span>

6 0

3 years ago

Read 2 more answers

Why does ice float on water?

WITCHER [35]

Explanation:

Ice floats on water because it's alil water compacted into 1 shape which is heavier, ice is also a solid at 1st so solid things also can float on water

6 0

3 years ago

Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli

Thepotemich [5.8K]

Answer:

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

Explanation:

Given:

Mass of Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = $v_{f}=?$

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

$m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}$

Substituting the values we get

$2\times 14 + 5\times 0 =(2+5)\times v_{f}$

$v_{f}=\dfrac{28}{7}=4\ m/s$

Therefore,

Final velocity of the coupled carts after the collision is

$v_{f}=4\ m/s$

8 0

3 years ago

A ball is in free fall after being dropped. What willthe speed of the ball be after 2 seconds of free fall?

Mazyrski [523]

So, the speed of the ball after 2 seconds after free fall is <u>20 m/s</u>.

<h3>Introduction</h3>

Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :

$\boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}}$

With the following conditions :

a = acceleration (m/s²)
$\sf{v_2}$ = speed after some time (m/s)
$\sf{v_1}$ = initial speed (m/s)
t = interval of time (s)

<h3>Problem Solving</h3>

We know that :

a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
$\sf{v_1}$ = initial speed = 0 m/s >> the keyword is free fall
t = interval of time = 2 s

What was asked :

$\sf{v_2}$ = speed after some time = ... m/s

Step by step :

$\sf{a = \frac{v_2 - v_1}{t}}$

$\sf{(a \times t) + v_1 = v_2}$

$\sf{(10 \times 2) + 0 = v_2}$

$\boxed{\sf{v_2 = 20 \: m/s}}$

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

8 0

3 years ago