Question

Steve tunes an old-fashioned radio that has an antenna made from a 3.0-cm-long solenoid with a cross-sectional area of 0.50 cm2 , composed of 300 turns of fine copper wire. Calculate the inductance of the coil assuming it is air-filled.

Answer 1

Answer:

$L = 1.88\times10^-^4 H$

Explanation:

It is given that,

Length of the coil, l = 3 cm = 0.03 m

Area of cross section of the coil, $A=0.5\ cm^2=0.00005\ m^2$

Number of turns in the coil, N = 300

inductance of the coil is

$L=\dfrac{\mu_oN^2A}{l}$

$L=\dfrac{4\pi\times 10^{-7}\times (300)^2\times 5\times 10^{-5}}{0.03}\\L = 1.88\times10^-^4 H$

So, the inductance of the coil is 1.88× 10⁻⁴H