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Cloud [144]
3 years ago
12

A "sun yacht" is a spacecraft with a large sail that is pushed by sunlight. Although such a push is tiny in everyday circumstanc

es, it can be large enough to send the spacecraft outward from the Sun on a cost-free but slow trip. Suppose that the spacecraft has a mass of 900 kg and receives a push of 20 N. (a) What is the magnitude of the resulting acceleration? If the craft starts from rest,(b) how far will it travel in 1 day and (c) how fast will it then be moving?
Physics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

acceleration = 0.022 m/s^2

distance = 8.3 x 10^7 m

speed = 1.9 x 10 ^3 m/s

Explanation:

the parameters given are:

mass = 900kg

force = 20N

  • from the formula force = mass x acceleration

acceleration = force / mass

acceleration = 20 / 900

acceleration = 0.022 m/s^2

  • distance travelled in 1 day (86,400 seconds) = (1/2) x a x t^2

   (1/2) x 0.022 x (86,400^2) = 8.3 x 10^7 m

  • speed of the sun yatch (v) = a x t

0.22 x 86400 = 1.9 x 10 ^3 m/s

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Which of the following is a good conductor of heat? 1. water 2. glass 3. wood 4. mercury​
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So the answer would be water based on the evidence shown below.

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3 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista
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The answer is 60 mph.

The speed (v) is distance (d) per time (t): v = d/t

Car A:
v1 = ?
t1 = 2 h
d1 = ?
___
v1 = d1/t1
d1 = v1 * t1

Car B:
v2 = ?
t2 = 1.5 h
d2 = ?
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v2 = d2/t2
d2 = v2 * t2

<span>Two cars traveled equal distances:
d1 = d2
</span>v1 * t1 = v2 * t2

<span>Car B traveled 15 mph faster than Car A:
v2 = v1 + 15


</span>v1 * t1 = v2 * t2
v2 = v1 + 15
________
v1 * 2 = (v1 + 15) * 1.5
2v1 = 1.5v1 + 22.5
2v1 - 1.5v1 = 22.5
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8 0
3 years ago
Students are asked to create roller coasters for marbles. Their goal is to design a coaster with the tallest possible hill that
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3 0
2 years ago
Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un
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Explanation:

Formula to determine the critical crack is as follows.

          K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}

  \gamma = 1,     K_{IC} = 24.1

  [/tex]\sigma_{y}[/tex] = 570

and,   \sigma_{f} = 570 \times \frac{3}{4}

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Hence, we will calculate the critical crack length as follows.

      a = \frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}

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Therefore, largest size is as follows.

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Thus, we can conclude that the critical crack length for a through crack contained within the given plate is 20.26 \times 10^{-4}.

4 0
3 years ago
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