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ASHA 777 [7]
3 years ago
6

Do longitude lines run horizontally (east-west) or vertically (north-south)?

Physics
1 answer:
nlexa [21]3 years ago
3 0
Longitude- Horizontal (East West)
Latitude- Vertical (North South)
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What is the acceleration of an 24 kg object that applies a force of 130N?
WITCHER [35]

Answer:

To find the acceleration of the object we have to apply Newton second law of motion that is F = mass × acceleration.

Explanation:

Given ,

F = 130N

M = 24kg

A = ?

F = m× a

then ,

130N = 24kg ×a

a = 130/24 = 5 m/s.

6 0
2 years ago
What do we call the movement of electric charge?<br> A. Power B. Voltage C. Resistance D. Current
Alex Ar [27]
D. Current

Hope I helped!
4 0
2 years ago
Read 2 more answers
A typical nuclear fission power plant produces about 1.00 GW of electrical power. Assume the plant has an overall efficiency of
mamaluj [8]

Answer:

mass consumed by 235U each day = 2 kg

Explanation:

electrical power produced = 1 GW = 1 × 10⁹ × (6.24151 × 10¹⁸ ) eV

                                            = 6.24151× 10²¹ MeV/s

thermal energy =  0.420 * 250 = 105 MeV

\dfrac{1 GW}{150 MeV}= \dfrac{6.24151\times 10^{21}}{105}

                                      = 5.94 × 10¹⁹ fission/second

                                       =5.94 × 10¹⁹× 24 × 60 ×60)

                                      =  5.13 × 10²⁴ fission/day

mu = 235.04393 ×  1.660× 10 ⁻²⁷ = 390.1729× 10⁻²⁷ Kg

M = mu ×5.13 × 10²⁴

   = 390.1729× 10⁻²⁷ ×5.13 × 10²⁴

M   =  2 kg(approx.)

mass consumed by 235U each day = 2 kg

3 0
3 years ago
You are driving on a freeway and notice a small car (very small) cut off a big truck. Explain why it is a bad idea for the small
Leno4ka [110]

Answer: small cars can stop and go fast big trucks can not

Explanation:

7 0
3 years ago
Knowing that a 0.90-kg object weighs 9.0 N , find the acceleration of a 0.90-kg stone in free fall . Express your answer to two
sasho [114]

Answer:

The value of acceleration of a stone in free fall is 10\ m/s^2.

Explanation:

Given that,

Mass of the object, m = 0.9 kg

Weight of the object, W = 9 N

We need to find the acceleration of a stone in free fall. The weight of an object is given by :

W = mg

g is the acceleration of the stone in free fall

So, g=\dfrac{W}{m}

g=\dfrac{9\ N}{0.9\ kg}

g=10\ m/s^2

So, the value of acceleration of a stone in free fall is 10\ m/s^2. Hence, this is the required solution.

7 0
3 years ago
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