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3 years ago

Do longitude lines run horizontally (east-west) or vertically (north-south)?

Physics

1 answer:

nlexa [21]3 years ago

3 0

Longitude- Horizontal (East West)
Latitude- Vertical (North South)

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2. A student drives 7.8-km trip to school and averages a speed of

Alekssandra [29.7K]

Answer:

The total time is: t=451.22 sec

The average speed is: V=34.57 m/s

Explanation:

Average speed

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

$\displaystyle V=\frac{x}{t}$

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

$\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec$

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

$\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec$

The total time is:

$t=239.26\ sec+211.96\ sec=451.22\ sec$

$\boxed{t=451.22\ sec}$

The average speed is:

$\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s$

$\boxed{\displaystyle V=34.57\ m/s}$

6 0

3 years ago

1 point

BaLLatris [955]

Answer:1

Explanation:

7 0

3 years ago

Two positive point charges of 12uc and Suc

GarryVolchara [31]

Answer:

54 N

Explanation:

We have two positive charges 12uC and 5 uC ,they are kept at a distance of 10cm.

We have a relation for force between two charges q1,q2 as

$F=\frac{kq1q2}{r^{2} }$

Value of k is $9*10^9$

On substituting the values into the equation we get,

$F=\frac{9*10^9*12*5}{10^9*10}\\\\ F=54N$

Hence the force between them is 54 N.

7 0

3 years ago

What acceleration will all objects experience during their flights through the air (on Earth)?

Salsk061 [2.6K]

Answer:

Explanation:

4 0

4 years ago

Read 2 more answers

Consider two vectors A~ and B~ and their resultant A~ +B~ . The magnitudes of the vectors A~ and B~ are, respectively, 18.2 and

saw5 [17]

Answer:

15.76°

Explanation:

Hi!

Let C~ = A~ + B~

Then

C~ dot A~ = |C| |A| cos Ф

C~ dot A~ = (A~ + B~) dot A~ = |A|^2 + |B| |A| cos(120)

Therefore

cos Ф = (|A| + |B| cos(120)) / |C| = 15.65/|C|

and

|C|^2 = |A|^2 + |B|^2 + 2 |B| |A| cos(120)

|C| = 16.261

cos Ф = 15.65/16.261

Ф = 15.76°

7 0

4 years ago