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olga55 [171]
3 years ago
12

A car weighing 15,000 is on a hydraulic lift platform measuring 10m^2. What is the area of the smaller piston if a force of 1,10

0N is used to lift the car?
Physics
1 answer:
Artemon [7]3 years ago
8 0

Answer:The pressure must be the same throughout the lift, so

 

P = F1/A1 = F2/A2 ⇒

 

A2 = (F2/F1)A1  

 

F2 = 1,100 N

F1 = 15,000 N

A1 = 10 m2

 

Plug in the numbers and evaluate A2.  The answer will come out in m2.

Explanation:

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Answer:

I'm pretty sure its 3m/s^2 for the acceleration but I don't know the force part sorry .

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I'm no expert or anything so I could be wrong but this is the best I can give you. Sorry

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quantitative

Explanation:

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a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at th
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... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
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s = 62.06 m

(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
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... find time
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