The first question's answer is :
If, F=ma
Then, 15N= 2.1kg (a)
15/2.1=a
7.14=a
Therefore, acceleration = 7.14m/s^2
sorry I am not sure about the second question :-(
1. Kicking a soccer ball
2.Playing tug of war
3.Bouncing a Ball
Answer:
Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis
Explanation:
The stiff wire 50.0cm long bent at a right angle in the middle
One section lies along the z axis and the other is along the line y=2x in the xy plane

tan θ = 2
Therefore,
slope m = tan θ = y / x

Then length of each section is 25.0cm
so, length vector of the wire is

And magnetic field is B = (0.318T)i
Therefore,

![\bar F = (20.0)[(0.112m)i +(0.224m)j-(0.250m)k \times 90.318T)i]](https://tex.z-dn.net/?f=%5Cbar%20F%20%3D%20%2820.0%29%5B%280.112m%29i%20%2B%280.224m%29j-%280.250m%29k%20%5Ctimes%2090.318T%29i%5D)
![= (20.0)(i(0)+j(-0.250)(0.318T)+k[0-(0.224m)(0.318T)]\\\\=(20.0)(-0.250)(0.318)j-(20.0)(0.224)(0.318T)\\\\=-(1.59N)j-(1.425N)k](https://tex.z-dn.net/?f=%3D%20%2820.0%29%28i%280%29%2Bj%28-0.250%29%280.318T%29%2Bk%5B0-%280.224m%29%280.318T%29%5D%5C%5C%5C%5C%3D%2820.0%29%28-0.250%29%280.318%29j-%2820.0%29%280.224%29%280.318T%29%5C%5C%5C%5C%3D-%281.59N%29j-%281.425N%29k)
Magnitude of the force is

Direction is

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis
Answer:
ΔK = 24 joules.
Explanation:
Δ
Work done on the object
Work is equal to the dot product of force supplied and the displacement of the object.
* Δ
Δ
can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δ
= (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).
This gives us
*
=
=
J
Answer:
The acceleration of the snowball is 0.3125
Explanation:
The initial speed of the snowball up the hill, u = 0
The speed the snowball reaches, v = 5 m/s
The length of the hill, s = 40 m
The equation of motion of the snowball given the above parameters is therefore;
v² = u² + 2·a·s
Where;
a = The acceleration of the snowball
Plugging in the values, we have;
5² = 0² + 2 × a × 40
∴ 2 × 40 × a = 5² = 25
80 × a = 25
a = 25/80 = 5/16
a = The acceleration of the snowball = 5/16 m/s².
The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .