Answer:
Explanation:
Given
Frequency of SHM is 
Amplitude of SHM is 
Cup begins to slip when it overcomes the friction force
Friction force 
Applied force 
and maximum acceleration during SHM is
To solve this we assume
that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 =284.15 x 2.50 / 303.15
<span>V2 = 2.34 L</span>
The 1kg ball would exert the smallest force.
As force = mass x gravity, this means that the smaller the mass (kg), the lesser the force.
When the mass is lighter (1kg):
Force = mass x gravity
Force = 1 x 9.8
Force = 9.8N
Compared to when the mass is heavier (10kg)
Force = mass x gravity
Force = 10 x 9.8
Force = 98N
Where this proves that the lighter the mass, the smaller the force exerted.
