3 years ago

When developing a design proposal, you will need to ask: *

1 answer:

6 0

Answer:

Last option : All of the above.

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Aria♡

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attached below

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3 years ago

A body of weight 300N is lying rough

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Horizontal force = 89.2 N

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The frictional force = coefficient of friction * magnitude of the force (weight of the body) * cos theta

Substituting the given values, we get -

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Water from an upper tank is drained into a lower tank through a 5 cm diameter iron pipe with roughness 2 mm. The entrance to the

nignag [31]

Answer:

Relative roughness = 0.04

Explanation:

Given that:

Diameter = 5 cm

roughness = 2 mm

At inlet:

Minor coefficient loss $k_{L1} = 0.4$

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Minor coefficient loss $k_{L2} = 1$

Height h = 4m

Length = 5 m

To find the relative roughness:

Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:

$e_r = \dfrac{e}{D}$