Answer : The crystal structure of Niobium is, BCC (Z=2)
Explanation :
Nearest neighbor distance, r =
Atomic mass of niobium (Nb) = 92.91 g/mole
Avogadro's number
First we have to calculate the cubing of edge length of unit cell for BCC and FCC crystal lattice.
For BCC lattice :
For FCC lattice :
Now we have to calculate the density of unit cell for BCC and FCC crystal lattice.
Formula used :
.............(1)
where,
= density
Z = number of atom in unit cell (for BCC = 2, for FCC = 4)
M = atomic mass
= Avogadro's number
a = edge length of unit cell
Now put all the values in above formula (1), we get
From this information we conclude that, the given density is approximately equal to the density of BCC unit lattice.
Therefore, the crystal structure of Niobium is, BCC (Z=2)
Answer:
Technician B is wrong while Technician A is right
Explanation:
In a worm gear steering system the steering wheel is connected to a shaft which turns the worm gear that is located inside of the Gear box and most excessive steering free play occurs in the Gear box and this is because the worm gear steering system consists of a gear that moves up and down whenever the steering is turned
Answer:
Flow velocity
50.48m/s
Pressure change at probe tip
1236.06Pa
Explanation:
Question is incomplete
The air velocity in the duct of a heating system is to be measured by a Pitot-static probe inserted into the duct parallel to the flow. If the differential height between the water columns connected to the two outlets of the probe is 0.126m, determine (a) the flow velocity and (b) the pressure rise at the tip of the probe. The air temperature and pressure in the duct are 352k and 98 kPa, respectively
solution
In this question, we are asked to calculate the flow velocity and the pressure rise at the tip of probe
please check attachment for complete solution and step by step explanation
Answer:
B. It can add to an engineer’s credentials and qualifications.
Explanation: