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djverab [1.8K]
4 years ago
11

Machine movement can be divided into what two main categories?

Engineering
2 answers:
pishuonlain [190]4 years ago
8 0

Answer:

motion and power

Explanation:

avanturin [10]4 years ago
8 0

Answer:motion and action

Explanation: i did motion and power but it was wrong.

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Which of the following is not caused by alcohol?
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Inhibited comprehension

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For this assignment, you will write a program to determine the time and date corresponding to an elapsed number of seconds since
Karolina [17]

A Python program should be written to produce output that corresponds to the given hour, minute, second, day of the month, month's name, year, and day of the week's name.

present_year=2016

present_month="January"

present_date="1"

present_day="Friday"

present_hour=0

present_minute=0

present_second=0

input<-from user(seconds)//taking imput from the user using Python program

   total_seconds=input

   //checking with seconds

   if(total_seconds<60)

       present_second+=total_seconds

   else

       total_minutes=total_seconds/60

       remaining_seconds=total_seconds-total_minutes*60

       present_second+=remaining_seconds

   //checking with minutes

   if(total_minutes<60)

       present_minute+=total_minutes

   else

       total_hours=total_minutes/60

       remaining_minutes=total_minutes-total_hours*60

       present_minute+=remaining_minutes

   //checklng with hours

   if(total_hours<24)

       present_hour+=total_hours

   else

       total_days=total_hours/24

       remaining_hours=total_hours-total_days*24

       present_hour+=remaining_hours

   //checking with days

   total_weeks=total_days/7

   remaining_day=total_days-total_weeks*7

   switch(remaining_day)

       case 1:

           present_day="Friday"

       case 2:

           present_day="Saturday"

       case 3:

           present_day="Sundayday"

       case 4:

           present_day="Monday"

       case 5:

           present_day="Tuesday"

       case 6:

           present_day="Wedday"

       case 7:

           present_day="Thursday"

   //checking with years    

   if(total_days>366)

       while(total_days)

           if(present_year%4==0)

               total_days-=366

               present_year+=1

           if(present_year%4!=4)

               total_days-=365

               present_year+=1

           if(present_year%4!=0&&total_days<365)

               break;

           if(present_year%4==0&&total_days<366)

               break;

   //checking with months and date

   if(total_days<=366)

       while(total_days)

           if(present_month="January")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="February"

                   present_date=0

           if(present_month="February")

               present_date++

               total_days--

               if(present_date==28&&present_year%4!=0)

                   present_month="March"

                   present_date=0

               if(present_date==29&&present_year%4==0)

                   present_month="March"

                   present_date=0

           if(present_month="March")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="April"

                   present_date=0        

           if(present_month="April")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="May"

                   present_date=0        

           if(present_month="May")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="June"

                   present_date=0        

           if(present_month="June")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="July"

                   present_date=0    

           if(present_month="July")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="August"

                   present_date=0    

           if(present_month="August")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="September"

                   present_date=0        

           if(present_month="September")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="October"

                   present_date=0    

           if(present_month="October")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="November"

                   present_date=0    

           if(present_month="November")

               present_date++

               total_days--

               if(present_date==30)

                   present_month="December"

                   present_date=0

           if(present_month="December")

               present_date++

               total_days--

               if(present_date==31)

                   present_month="January"

                   present_date=0

//printing present time

print present_hour:present_minute:present_second present_date present_month present_year present_day          

Learn more about Python program here:

brainly.com/question/28691290

#SPJ4          

3 0
2 years ago
(a) A 10.0-mm-diameter Brinell hardness indenter produced an indentation 2.3 mm in diameter in a steel alloy when a load of 1000
vampirchik [111]

Answer:

(a)  We are asked to compute the Brinell hardness for the given indentation. for HB, where P= 1000 kg, d= 2.3 mm, and D= 10 mm.  

Thus, the Brinell hardness is computed as

HB=2P/\pi D{D-\sqrt{D^2-d^2}

=2*1000hg/\pi (10mm)[10mm-\sqrt{(1000^2-(2.3mm)^2} ]

(b)    This  part  of  the  problem  calls  for  us  to  determine  the  indentation diameter d which  will  yield  a  270  HB  when P=  500  kg.  

d=\sqrt{D^2-[D-\frac{2P}{(HB)\pi D} } ]^2\\=\sqrt{(10mm)^2-[10mm-\frac{2*500}{450( \pi10mm)} } ]^2

6 0
4 years ago
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