It is known as a basic unit of all living things.

The battery for a certain cell phone is rated at 3.70 V. According to the manufacturer it can produce math]3.15 \times 10^{4} J[

AysviL [449]

Answer:

The average current that this cell phone draws when turned on is 0.451 A.

Explanation:

Given;

voltage of the phone, V = 3.7 V

electrical energy of the phone battery, E = 3.15 x 10⁴ J

duration of battery energy, t = 5.25 h

The power the cell phone draws when turned on, is the rate of energy consumption, and this is calculated as follows;

$P = \frac{E}{t}$

where;

P is power in watts

E is energy in Joules

t is time in seconds

$P = \frac{3.15*10^4}{5.25*3600s} = 1.667 \ W$

The average current that this cell phone draws when turned on:

P = IV

$I = \frac{P}{V} =\frac{1.667}{3.7} = 0.451 \ A$

Therefore, the average current that this cell phone draws when turned on is 0.451 A.

5 0

3 years ago

If you increase the elasticity of a material, what happens to the speed of a mechanical wave going through it?

Sophie [7]

Answer:

At the molecular level, materials are held together by bonds, which act like springs for small displacements from the equilibrium spacing between neighboring atoms. Push the atoms close, the bond pushes back to keep them apart. Pull them apart, the bond pulls the atoms closer. For those small displacements, it acts like a spring

The speed of the wave will be related to the stiffness of of those springs - you compress the material - how quickly do all of those little springs rebound and push their neighboring atoms away, sending that wave of compression through the material.

Explanation:

5 0

2 years ago

What are possible units for impulse? Check all that apply. kg • m kg • N • s N • m

Vlada [557]

We know that impulse is simply the product of Force and time:

Impulse = Force * time

Since Force has a unit of Newton or kg m/s^2 and time is in seconds, therefore impulse can have units as:

N s

or

4 0

3 years ago

Light of wavelength 476.1 nm falls on two slits spaced 0.29 mm apart. What is the required distance from the slits to the screen

stich3 [128]

Answer:

The distance is $D = 2.6 \ m$

Explanation:

From the question we are told that

The wavelength of the light is $\lambda = 476.1 \ nm = 476.1 *10^{-9} \ m$

The distance between the slit is $d = 0.29 \ mm = 0.29 *10^{-3} \ m$

The between the first and second dark fringes is $y = 4.2 \ mm = 4.2 *10^{-3} \ m$

Generally fringe width is mathematically represented as

$y = \frac{\lambda * D }{d}$

Where D is the distance of the slit to the screen

Hence

$D = \frac{y * d}{\lambda }$

substituting values

$D = \frac{ 4.2 *10^{-3} * 0.29 *10^{-3}}{ 476.1 *10^{-9} }$

$D = 2.6 \ m$

7 0

3 years ago

A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can

Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

$\mu mg = m\frac{v^2}{r}$

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

$\mu$ is the coefficient of friction between the tires and the road