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Sergio [31]
4 years ago
11

The vibrations produced by a jackhammer are used to break up pavement. What type of waves did/does the jackhammer produce into t

he ground? ...?
Physics
1 answer:
klio [65]4 years ago
8 0
<span>P waves 

P-waves are sometimes called pressure waves, and sometimes they are called longitudinal waves. P-waves are transmitted through the Earth’s interior with a backwards and forwards motion along the line of travel, by alternating compression and dilatation. A jack hammer creates P-waves. They are capable of passing through any type of material they encounter, including the liquid of the Earth’s outer core, although they 
will be bent and deflected when they pass across the boundaries separating 
layers of different densities. 


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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What description refers to fog?
wolverine [178]
I think the answer is D
4 0
3 years ago
In si units, the electric field in an electromagnetic wave is described by ey = 104 sin(1.40 107x − ωt). (a) find the amplitude
melamori03 [73]
Answers:
(a) B_o  = 0.3466μT
(b) \lambda = 0.4488μm
(c) f = 6.68 * 10^{14}Hz

Explanation:
Given electric field(in y direction) equation:
E_y = 104sin(1.40 * 10^7 x -\omega t)

(a) The amplitude of electric field is E_o = 104. Hence

The amplitude of magnetic field oscillations is B_o =  \frac{E_o}{c}
Where c = speed of light

Therefore,
B_o =  \frac{104}{3*10^8} = 0.3466μT (Where T is in seconds--signifies the oscillations)

(b) To find the wavelength use:
\frac{2 \pi }{\lambda} = 1.40 * 10^7
\lambda =  \frac{2 \pi}{1.40} * 10^{-7}
\lambda =  0.4488μm

(c) Since c = fλ
=> f = c/λ

Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f = 6.68 * 10^{14}Hz


6 0
3 years ago
If wave A has twice the amplitude and three times the frequency as wave B, then the energy carried by wave A must be ____ times
soldier1979 [14.2K]

Answer:

4 times

Explanation:

As we know that the energy of a wave is directly proportional to the square of the amplitude of the wave,

Here, the amplitude of the wave A is twice as compared to B.

So, the energy of wave A is 4 times the energy of wave B.

4 0
3 years ago
Two identical trucks have mass 5100 kg when empty, and the maximum permissible load for each is 8000 kg. the first truck, carryi
Oksanka [162]
<span>The 2nd truck was overloaded with a load of 16833 kg instead of the permissible load of 8000 kg. The key here is the conservation of momentum. For the first truck, the momentum is 0(5100 + 4300) The second truck has a starting momentum of 60(5100 + x) And finally, after the collision, the momentum of the whole system is 42(5100 + 4300 + 5100 + x) So let's set the equations for before and after the collision equal to each other. 0(5100 + 4300) + 60(5100 + x) = 42(5100 + 4300 + 5100 + x) And solve for x, first by adding the constant terms 0(5100 + 4300) + 60(5100 + x) = 42(14500 + x) Getting rid of the zero term 60(5100 + x) = 42(14500 + x) Distribute the 60 and the 42. 60*5100 + 60x = 42*14500 + 42x 306000 + 60x = 609000 + 42x Subtract 42x from both sides 306000 + 18x = 609000 Subtract 306000 from both sides 18x = 303000 And divide both sides by 18 x = 16833.33 So we have the 2nd truck with a load of 16833.33 kg, which is well over it's maximum permissible load of 8000 kg. Let's verify the results by plugging that mass into the before and after collision momentums. 60(5100 + 16833.33) = 60(21933.33) = 1316000 42(5100 + 4300 + 5100 + 16833.33) = 42(31333.33) = 1316000 They match. The 2nd truck was definitely over loaded.</span>
6 0
4 years ago
light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li
lapo4ka [179]

Answer:

The distance traveled in 1 year is: 3.143*10^{16}ft

Explanation:

Given

s = 982,080,000 ft/s --- speed

t = 32,000,000 s --- time

Required

The distance traveled

This is calculated as:

Speed = \frac{Distance}{Time}

So, we have:

Distance = Speed * Time

This gives:

Distance = 982,080,000 ft/s * 32,000,000 s

Distance = 982,080,000  * 32,000,000ft

Distance = 3.143*10^{16}ft -- approximated

5 0
3 years ago
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