From left to right, follow the dots in line 1 with your finger. Count a steady beat out loud, and time your motion so your finge
2 answers:
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Answer:
The rope must have a force of 10084,21 N
Explanation
Acceleration calculation
The car acceleration is equal to the acceleration of the truck
ac: car acceleration
at: truck acceleration)
equation(1)
Known information:
vi = Initial speed = 0, ti = initial time = 0
vf = Final speed = 13 , t = final time =5 s
We replaced the known information in the equation(1):
Dynamic analysis
The forces acting on the car are the following:
Wc: Car weight
N: normal force, road force on the car
Ff: Friction force
T: Force of tension
Car weight calculation:
mc = Car mass = 2230kg
g = Gravity acceleration=9.8
Normal force calculation:
Newton's first law
Friction force calculation (Ff):
We have the formula to calculate the friction force:
Ff = μk * N Equation (3)
μk kinetic coefficient of friction
We know that μk = 0.373and N= 21854N ,then:
Calculation of the tension force in the rope (T):
Newton's Second law
T=10084,21 N
Answer: The rope must have a force of 10084,21 N
Answer:
See the answers below.
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
y - yo = Fall distance [m]
Vo = initial velocity = 0 (dropped)
t = time = 6.5 [s]
g = gravity acceleration = 9.8 [m/s²]
Now replacing:
The question is related to the distance between the points where the ball was dropped and the ground.
The variables used are gravitational acceleration, time, fall distance, initial velocity.
The speed of the ball is B. 5 meters per second
Explanation:
For an object in uniform motion (= at constant velocity), the speed can be calculated using the equation
where
v is the speed
d is the distance covered
t is the time taken
For the ball in this problem:
d = 50 m is the distance covered
t = 10 s is the time taken
Substituting, we find the speed:
Learn more about speed:
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