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murzikaleks [220]
3 years ago
7

From left to right, follow the dots in line 1 with your finger. Count a steady beat out loud, and time your motion so your finge

r crosses a dot at the end of each beat. Don’t pause at the dots, and move as smoothly as you can. A good way to count is to say or think “1 Mississippi, 2 Mississippi,” and so on. Is your finger moving at a constant rate, or is the rate changing?
Physics
2 answers:
lora16 [44]3 years ago
8 0
It changes as i move my finger.
Gnoma [55]3 years ago
4 0

Answer:

A) The rate changes as i move my finger

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If your hair blower isnt rated for 220- 230V(this is the voltage in EU) you are most likely going to burn it.
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Does the moon fall partly into earth's shadow when it is n "full"?
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An object of unknown mass is initially at rest and dropped from a height h. It reaches the ground with a velocity v1 . The same
Hatshy [7]

Answer:

v_2=\sqrt{2}v_1

Explanation:

The velocity v₁ can be calculated with the kinematic formula:

v_1^{2} =v_0^{2} +2gh

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v_1=\sqrt{2gh}

Where g is the acceleration due to gravity. Now, the velocity v₂ can be calculated with the same formula, but now the initial velocity is v₁:

v_2^{2}=v_1^{2} +2gh

Substituting v₁ in this expression and solving for v₂, we get:

v_2^{2}=(\sqrt{2gh} )^{2} +2gh=4gh\\\\\implies v_2=\sqrt{4gh}=2\sqrt{gh}

Now, dividing v₂ over v₁, we get the expression:

\frac{v_2}{v_1}=\frac{2\sqrt{gh} }{\sqrt{2gh}}=\sqrt{2}\\   \\\implies v_2=\sqrt{2}v_1

It means that v₂ is √2 times v₁.

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4 years ago
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