Answer:
f =63.64Hz
Explanation:
The equation of the transverse periodic wave
y = 0.005 sin(20.0x + 2ft)
From the equation we can deduce that
Amplitude A = 0.005
Wave number K = 20
Angular frequency w = 2πf
We are asked to find the frequency (f)
the formular for the wave number is given as K = 2π / lambda
Lambda = 2π/ K
Lamda is the wavelength
= 2 × 3.142 /20
= 0.3142m
The velocity of the wave is expressed as v = frequency × lamba (wavelength)
Frequency = velocity / wavelength
f = 20/ 0.3142
f = 63.65Hz