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gayaneshka [121]
2 years ago
6

A transverse periodic wave is established on a string. The wave is described by the expression y = 0.005 sin(20.0x + 2ft) where

y is in meters when x and t are in meters and seconds, respectively. If the wave travels with a speed of 20.0 m/s, what is its frequency, f?
Physics
1 answer:
Crank2 years ago
6 0

Answer:

f =63.64Hz

Explanation:

The equation of the transverse periodic wave

y = 0.005 sin(20.0x + 2ft)

From the equation we can deduce that

Amplitude A = 0.005

Wave number K = 20

Angular frequency w = 2πf

We are asked to find the frequency (f)

the formular for the wave number is given as K = 2π / lambda

Lambda = 2π/ K

Lamda is the wavelength

= 2 × 3.142 /20

= 0.3142m

The velocity of the wave is expressed as v = frequency × lamba (wavelength)

Frequency = velocity / wavelength

f = 20/ 0.3142

f = 63.65Hz

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devlian [24]

Answer:

2m₁m₃g / (m₁ + m₂ + m₃)

Explanation:

I assume the figure is the one included in my answer.

Draw a free body diagram for each mass.

m₁ has a force T₁ up and m₁g down.

m₂ has a force T₁ up, T₂ down, and m₂g down.

m₃ has a force T₂ up and m₃g down.

Assume that m₁ accelerates up and m₂ and m₃ accelerate down.

Sum of the forces on m₁:

∑F = ma

T₁ − m₁g = m₁a

T₁ = m₁g + m₁a

Sum of the forces on m₂:

∑F = ma

T₁ − T₂ − m₂g = m₂(-a)

T₁ − T₂ − m₂g = -m₂a

(m₁g + m₁a) − T₂ − m₂g = -m₂a

m₁g + m₁a + m₂a − m₂g = T₂

(m₁ − m₂)g + (m₁ + m₂)a = T₂

Sum of the forces on m₃:

∑F = ma

T₂ − m₃g = m₃(-a)

T₂ − m₃g = -m₃a

a = g − (T₂ / m₃)

Substitute:

(m₁ − m₂)g + (m₁ + m₂) (g − (T₂ / m₃)) = T₂

(m₁ − m₂)g + (m₁ + m₂)g − ((m₁ + m₂) / m₃) T₂ = T₂

(m₁ − m₂)g + (m₁ + m₂)g = ((m₁ + m₂ + m₃) / m₃) T₂

m₁g − m₂g + m₁g + m₂g = ((m₁ + m₂ + m₃) / m₃) T₂

2m₁g = ((m₁ + m₂ + m₃) / m₃) T₂

T₂ = 2m₁m₃g / (m₁ + m₂ + m₃)

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What type of machine is used to measure the location of an earthquake epicenter.
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Answer:

Seismometer

Explanation:

Seismometer measures Earth quake epicenter while seismograph measures Earth quake size

8 0
2 years ago
Two identical cylindrical vessels with their bases at the same level each contain a liquid of density 1.23 g/cm3. The area of ea
motikmotik

Explanation:

Work done by gravity is given by the formula,

           W = \rho A (h_{1} - h)g (h - h_{2}) ......... (1)

It is known that when levels are same then height of the liquid is as follows.

           h = \frac{h_{1} + h_{2}}{2} ......... (2)

Putting value of equation (2) in equation (1) the overall formula will be as follows.

       W = \frac{1}{4} \rho gA(h_{1} - h_{2})^{2})

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           = 0.689 J

Thus, we can conclude that the work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.689 J.

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