Question

If a ball is dropped and takes 6.5 seconds to hit the ground below. How far did it fall? Remember in free fall g= -9.8 m/s/s. What is this question asking you to solve for? What variables are being used?

Answer 1

Answer:

See the answers below.

Explanation:

To solve this problem we must use the following equation of kinematics.

$y=y_{o}+v_{o}*t+\frac{1}{2}*g*t^{2}$

where:

y - yo = Fall distance [m]

Vo = initial velocity = 0 (dropped)

t = time = 6.5 [s]

g = gravity acceleration = 9.8 [m/s²]

Now replacing:

$y-y_{o}=0 +\frac{1}{2} *9.8*6.5^{2}\\y-y_{o}=207 [m]$

The question is related to the distance between the points where the ball was dropped and the ground.

The variables used are gravitational acceleration, time, fall distance, initial velocity.