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2 years ago

Alka-Seltzer is pure NaHCO3 True or false?

Chemistry

1 answer:

blondinia [14]2 years ago

4 0

Answer:

falso

Explanation:

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Round 0.007062 to 4 significant numbers

mafiozo [28]

Answer

its already rounded

Explanation:

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3 years ago

What was the name for the secret code used by many alchemists?

ahrayia [7]

Answer:

A. Zodiac

B. Palingenesis

C. Palabra mysteria

D. Decknamen

The correct answer is D. Decknamen.

Explanation:

5 0

2 years ago

How does an atom change if all of its electrons are removed?<br> .

Soloha48 [4]

Answer:

If an atom looses all of its electrons then it will become positively charged. It will also turn into an Ion.

Explanation:

4 0

3 years ago

What mass of gallium oxide, Ga₂O3, can be prepared from

Degger [83]

Answer:

(70 x 2 + 16 x 3) x 29/70 x 2 = 38,9428571 g.

Explanation:

7 0

2 years ago

A chemist uses hot hydrogen gas to convert chromium(III) oxide to

Darya [45]

Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$

Explanation:

The reaction equation for given reaction is as follows.

$Cr_{2}O_{3} + 3H_{2} \rightarrow 2Cr + 3H_{2}O$

Here, 1 mole of $Cr_{2}O_{3}$ reacts with 3 moles of $H_{2}$ .

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide $(Cr_{2}O_{3})$ is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of $Cr_{2}O_{3}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol$

Now, moles of $H_{2}$ .given by 0.5 mol of $Cr_{2}O_{3}$ is calculated as follows.

$0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}$

As molar mass of $H_{2}$ is 2.016 g/mol. Therefore, mass of $H_{2}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g$

Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$ .

7 0

3 years ago