Answer: S<span>peed = 60.11 miles per hour
</span>
To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time.
<span>speed = distance/time</span>
The angle between the two vectors is 126° 52' 11".
The given parameters;
vector A = 3.00i + 1.00j
vector B = 1.00i + 3.00j
The angle between the two vectors is calculated as follows;

The dot product of vectors A and B is calculated as;
A.B = ( 3i + 1j ) . ( 1i +3j )
= ( 3 × 1 ) + ( 1 × 3 )
= 3 + 3
= 6
The magnitude of vectors A and B is calculated as;
|A| = ![\sqrt[]{3^2 + 1^2} = \sqrt[]{10} \\](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%5E2%20%2B%201%5E2%7D%20%3D%20%5Csqrt%5B%5D%7B10%7D%20%5C%5C)
|B| = ![\sqrt[]{1^2 + 3^2} = \sqrt[]{10} \\](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B1%5E2%20%2B%203%5E2%7D%20%3D%20%5Csqrt%5B%5D%7B10%7D%20%5C%5C)
The angle between in two vectors is calculated as;
![Cos \theta = \frac{6}{\sqrt[]{10}\sqrt[]{10} } \\\\Cos \theta = \frac{6}{\ 10 }\\\\Cos \theta = 0.6\\\\\theta = cos^-^1 (0.6)\\\\\theta = 126\\](https://tex.z-dn.net/?f=Cos%20%5Ctheta%20%3D%20%5Cfrac%7B6%7D%7B%5Csqrt%5B%5D%7B10%7D%5Csqrt%5B%5D%7B10%7D%20%20%7D%20%5C%5C%5C%5CCos%20%5Ctheta%20%3D%20%5Cfrac%7B6%7D%7B%5C%2010%20%7D%5C%5C%5C%5CCos%20%5Ctheta%20%3D%200.6%5C%5C%5C%5C%5Ctheta%20%3D%20cos%5E-%5E1%20%280.6%29%5C%5C%5C%5C%5Ctheta%20%3D%20126%5C%5C)
Therefore, the angle between the two vectors is 126° 52' 11".
Learn more about vectors here:
brainly.com/question/25705666
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Answer:
Explanation:
Acceleration of gravity on the surface of
Neptune is given
g' = G M/R^2,
where M is the planet's mass.
M g' will be the apparent weight registed at the poles.
G is the universal constant of gravity
The "apparent weight" at the equator will be
reduced from M g' by the centripetal force M
R w^2, where w is the rotational angular
velocity in radians/s), which you can deduce
from the 16 hour length of a day.
Answer:
Value of 
Explanation:
We have given
In first case resistance is
and current is 1.8 A
Let the potential difference is v
So
----eqn 1
In second case resistance is
and current is 1.6 A and potential difference will be as it is a series connection
So
----eqn 2
From eqn 1 and eqn 2


Answer:
c it does not move as the tire stops and applys friction
Explanation: