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slava [35]
3 years ago
12

One student suggests using a front-loading washing machine instead of a top-loading washing machine to conserve water. Which of

these statements best describes the suggestion made by the student?
a. It is practical because it is easy to implement.
b. It is practical because a top-loading machine uses much more water than a front-loading machine.
c. It is not practical because all washing machines use the same amount of water.
d. It is not practical because front-loading machines are more expensive than top-loading machines.
Physics
1 answer:
mariarad [96]3 years ago
3 0
B) <span> It is practical because a top-loading machine uses much more water than a front-loading machine.

Front-loading washing machines are able to better conserve water by automatically maintaining the same water level throughout the wash, while top-loading washing machines generally begin the cycle by filling up the barrel to a certain point. </span>
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While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0
3 years ago
Strontium 3890Sr has a half-life of 28.5 yr. It is chemically similar to calcium, enters the body through the food chain, and co
patriot [66]

Answer:

Thus the time taken is calculated as 387.69 years

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t = \frac{-4\times 28.5}{log\frac{1}{2}}

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