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nevsk [136]
3 years ago
9

A 50 kg bear climbed on the tree branch 10 meters above the ground. If the bear descends to 5 meters above the ground, its poten

tial energy will be decreased by
A/ 4900 J
B/ 2450 J
C/ 2540 J
D/ 2500 J ​
Physics
1 answer:
Simora [160]3 years ago
6 0
<h3>Option A. 4900 J or joules</h3>
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A 0.15 kg mass is suspended from a vertical spring and descends a distance of 4.6 cm, after which it hangs at rest. An additiona
ch4aika [34]

Answer:

The total extension = 19.9 cm

Work done in stretching the spring through both displacement = <em>0.633 J.</em>

Explanation:

From Hook's law,

F  = ke .................................... Equation 1.

Where F = force or weight, k = force constant of the spring, e = extension.

making k the subject of the equation,

k = F/e .......................... Equation 2

Given: F = W = mg = 0.15(9.8) = 1.47 N, e = 4.6 cm = 0.046 m.

k = 1.47/0.046

k = 31.96 N/m.

When an additional mass of 0.5 kg is suspended,

Total mass suspended(M₁) = 0.15+0.5 = 0.65 kg

Total Weight (W₁) = 0.65(9.8) = 6.37 N.

k = 31.96 N/m

Substituting into equation 1

6.37 = 31.96e

e = 6.37/31.96

e = 0.199 m

e = 19.9 cm

Thus the total extension = 19.9 cm

a.

Work done in stretching the spring  through both displacement

W = 1/2ke²..................... Equation 3

Where W = work done, k = spring constant, e = extension.

Given: k = 31.96 N/m, e = 0.199 m

Substituting into equation 3

W = 1/2(31.96)(0.199)²

<em>W = 0.633 J.</em>

5 0
3 years ago
On Ramesh’s13th birthday, his father invited all his friends and their relatives. It was a big party with lots of food and DJs.
BaLLatris [955]
I go inside and take a nap normally that will help maybe play music
3 0
3 years ago
I NEED THIS A SOON AS POSSIBLE
vivado [14]

Work is done when spring is extended or compressed. Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.

6 0
3 years ago
Read 2 more answers
Why do thunderstorms most often occur in the summer months?
777dan777 [17]

Answer:

Because moisture and warmth are crucial to thunderstorms

6 0
3 years ago
A solid sphere of diameter D = 26 cm has a charge of Q = 4 nano-coulombs uniformly distributed on it. Calculate the magnitude of
kozerog [31]

Answer:

E = 4.83  N/ C

Explanation:

If we have a uniform charge sphere we can use the following formulas to calculate the Electric field due to the charge of the sphere:

E= \frac{k*Q}{r^{2} } : Formula (1) To calculate the electric field in the region outside the sphere r ≥ a

Where:

K: coulomb constant (N*m²/C²)

a: sphere radius (m)

Q:  Total sphere charge (C)

r : Distance from the center of the sphere to the region where the electric field is calculated (m)

Equivalences

1nC=10⁻⁹C

1cm= 10⁻²m

Data

k= 9*10⁹ N*m²/C²

Q=4nC=4 *10⁻⁹C

D = 26 cm = 26*10⁻²m = 0.26m

a = D/2 = 0.13m

r= R+a = 2.6 m+ 0.13m = 2.73m

Problem development

Magnitude of the electric field at r = 2.73m from the center of the sphere  

r>a , We apply the Formula (1) :

E= \frac{k*Q}{r^{2} }

E= \frac{9*10^{9}*4*10^{-9} }{2.73^{2} }

E= 4.83 N/ C

3 0
3 years ago
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