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Bess [88]
3 years ago
8

Mole ratios how can the coefficients in a chemical equation be interpreted

Chemistry
1 answer:
navik [9.2K]3 years ago
8 0

Answer:

The coefficient in a balanced chemical equation  indicates the mole ratio of both reactants and products.  

Explanation:

For example lets consider the reation between Hydrogen and Oxygen to form water:

2H2 + O2 ----------------------- 2H2O

In this reaction, the coefficients of the balanced reaction can be transformed to Mole ratio according to Avogadro's Law which states that at standard temperature and pressure, equal volume of gases contain the same  number of moles.

So the mole ratio for the above equation is  the  ratio of the coefficient:

2moles     :     1 mole               :          2 moles

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Process of transformation of CH3CH2CH2CH2CL to CH3CH(OH)CH(OH) CH3​
egoroff_w [7]

Answer:

Prefixes for carbon chain length are  

1 carbon = meth  

2 carbon = eth  

3 = prop  

4 = but  

5 = pent  

6 = hex  

7 = hept  

8 = oct  

9 = non  

10 = dec

Explanation:

4 0
3 years ago
Which physical property is being used to separate the mixtures in each of the following cases?
kirill115 [55]

I think that this is

6 0
3 years ago
The pressure of nitrogen gas at 35°C is changed from 0.89 atm to 4.3 atm. What will be its final temperature in Kelvin?
Alja [10]

Answer: The final temperature in Kelvin is 1488

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=0.89atm\\T_1=35^0C=(35+273)K=308K\\P_2=4.3atm\\T_2=?

Putting values in above equation, we get:

\frac{0.89}{308}=\frac{4.3}{T_2}\\\\T_2=1488K

Hence, the final temperature in Kelvin is 1488

8 0
3 years ago
Separate a mixture of sand, common salt, copper pieces and iron fillings. Also measure the amount of common salt in the mixture.
Neporo4naja [7]

Answer:

Explanation:

This question seeks to test the knowledge of separation techniques.

From the narration in the question, the first separation to be done is the removal of Iron fillings by the use of magnet (magnetic separation). Since Iron is magnetic, the iron fillings will be attracted by the magnet hence removing the iron fillings from the mixture.

The second constituent to be removed will be the copper pieces by the use of a sieve (sieving). Copper pieces have relatively larger sizes than sand and common salt, hence a sieve (which separates particles based on size) can be used to remove the copper pieces from the mixture.

What will be left in the mixture after the processes above will be salt and water. This mixture will have to be dissolved in water; the salt will dissolve in water while the sand will not. After which, filtration will be done to remove the sand which will be collected on the filter paper as filtride and the salt solution will pass through the filter paper as filtrate.

The salt solution can then be evaporated to dryness to retrieve the solid salt from the solution.

The amount of salt in the mixture can then be measured using a weighing balance.

Some of safety measures to be taken during the course of this experiment includes performing the experiment in an airtight and controlled environment. Lab coat and hand gloves should be worn during the course of the experiment. The evaporation to dryness should not be done close to an inflammable material/substance

5 0
3 years ago
A client presents with fatigue, nausea, vomiting, muscle weakness, and leg cramps. The laboratory values are as follows: sodium
Ganezh [65]

Answer: The laboratory value of potassium (3.0 mmol / L) is consistent with the client's symptoms of hypokalemia.

Explanation:

Hello!

Let's solve this!

Hypokalemia is a disorder in the body's electrolyte balance, when the decrease in blood potassium (K) ion levels is below 3.5 mmol / L. Potassium losses can occur through the digestive tract: such as vomiting and

diarrhea The most frequent symptoms of potassium loss include: tiredness, muscle weakness and cramping.

In conclusion, the laboratory value of potassium (3.0 mmol / L) is consistent with the client's symptoms of hypokalemia.

6 0
4 years ago
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