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Ugo [173]
1 year ago
13

A motorcycle moving at 18 m/s decelerates at a rate of 3.6 m/s². What is the car's

Physics
1 answer:
Gekata [30.6K]1 year ago
5 0

Answer:

V = 3.6 m/s

Explanation:

Given:

V₀ = 18 m/s

a = - 3,6 m/s²  (The motorcycle is slowing down!)

t = 4 s

____________

V - ?

Motorcycle speed:

V = V₀ + a·t

V = 18 + (-3.6)·4 = 3.6 m/s

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n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us
barxatty [35]

Answer:

The answer is "(1.265 \pm 0.010) \ s \ and \ 0.709 \%"

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\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2}  \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}

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 T_{theo} = (1.265 \pm 0.010) \ s

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\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100

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