A motorcycle moving at 18 m/s decelerates at a rate of 3.6 m/s². What is the car's
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To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzmann law which establishes that a black body emits thermal radiation with a total hemispheric emissive power (W / m²) proportional to the fourth power of its temperature.
Heat flow is obtained as follows:
Where,
F =View Factor
A = Cross sectional Area
Stefan-Boltzmann constant
T= Temperature
Our values are given as
D = 0.6m
The view factor between two coaxial parallel disks would be
Then the view factor between base to top surface of the cylinder becomes . From the summation rule
Then the net rate of radiation heat transfer from the disks to the environment is calculated as
Therefore the rate heat radiation is 780.76W
There are two ways to find energy. Energy=F*d=mv^2. We can use this relationship to find v:
To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:
Where,
F = Force
r = Radius
Replacing we have that,
The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore
Finally, angular acceleration is a result of the expression of torque by inertia, therefore
PART B)
The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians , therefore