Answer:
(A) NaOH and Ca(OH)2: Ca(OH)2
(B) MgCl2 and MgF2: MgF2
(C) Agl and KI: AgI
(D) NH4Cl and PbCl2: PbCl2
Explanation:
We need to see the solubility in water, at similar temperatures, for each compound and see which one is less soluble than the other:
NaOH: 1000 g/L (25 °C)
Ca(OH)2: 1.73 g/L (20 °C)
MgCl2: 54.3 g/100 mL (20 °C)
MgF2: 0.013 g/100 mL (20 °C)
Agl: 3×10−7g/100mL (20 °C)
KI: 140 g/100mL (20 °C)
NH4Cl: 383.0 g/L (25 °C)
PbCl2: 10.8 g/L (20 °C)
After the comparison made we can conclude that the less soluble, after saturation of water, will precipitate first.
Answer:
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Explanation:
Answer:
Hydrogen has only 1 valence electron in its outermost shell.
Explanation:
Answer:
0.453 moles
Explanation:
The balanced equation for the reaction is:
2Fe(s) + 3O2(g) ==> 2Fe2O3
From the equation, mass of O2 involved = 16 x 2 x 3 = 96g
mass of Fe2O3 involved = [(2x26) + 3 x 16] x 2
= 100g
Therefore 96g of O2 produced 100g of Fe2O3
32.2g of O2 Will produce 100x32.2/96
= 33.54g of Fe2O3
Converting it to mole using number of mole = mass/molar mass
but molar mass of Fe2O3 = 26 + (16 X 3)
= 74g/mole
Therefore number of mole of 33.54g of Fe2O3 = 33.54/74
= 0.453 moles
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