How would a flood be a limitation for synthetic polymers that rely on natural rubber in its production?

2 answers:

4 0

Answer : Synthetic polymer production is directly not dependent on the climatic effects; but in the floods if the rubber plants are harmed or the production is hampered or by limited availability of rubber plants due to floods can deeply effect the synthetic polymer manufacturing industry which are dependent on natural rubber plants. So, indirectly it may hamper the production of synthetic polymers.

Gnom [1K]3 years ago

3 0

Answer: just put synthetic polymer

Explanation: Synthetic polymer production is directly not dependent on the climatic effects; but in the floods if the rubber plants are harmed or the production is hampered or by limited availability of rubber plants due to floods can deeply effect the synthetic polymer manufacturing industry which are dependent on natural rubber plants. So, indirectly it may hamper the production of synthetic polymers.

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Which kind of force is a dipole-dipole force?

dexar [7]

Answer:

Explanation:

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lukranit [14]

I think you want to ask about Keq. At equilibrium, we can know [SO2Cl2] is 2.2*10-2 M -1.3*10-2M=9*10^-3 M. And [SO2]=[Cl2]. So the Keq=1.88*10^-2.

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When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°

dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.30^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant =

m= molality = $\frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579$