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masha68 [24]
3 years ago
14

What is the speed of light ?​

Physics
1 answer:
Brrunno [24]3 years ago
3 0

Answer:

299792458 metres per second

Explanation:

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Propels in the opposite direction

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A small mailbag is released from a helicopter that is descending steadily at 2.52 m/s. (a) After 4.00 s, what is the speed of th
gogolik [260]

Answer: 41.72m/s

Explanation: v= u + gt

V = 2.52 + 9.8(4.00)

V = 41.72m/s

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2 years ago
Should i beat up my sibling cause they mean to me?
Vlada [557]

no thats messed up lol

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3 years ago
. If she
I am Lyosha [343]

Answer:

9 meters

Explanation:

Given:

Mass of Avi is, m=40\ kg

Spring constant is, k=176,400\ N/m

Compression in the spring is, x=20\ cm=0.20\ m

Let the maximum height reached be 'h' m.

Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.

So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.

Decrease in elastic potential energy is given as:

EPE=\frac{1}{2}kx^2\\EPE=\frac{1}{2}\times 176400\times (0.20)^2\\EPE=88200\times 0.04=3528\ J

Now, increase in gravitational potential energy is given as:

GPE=mgh=40\times 9.8\times h=392h

Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,

392h=3528\\\\h=\frac{3528}{392}\\\\h=9\ m

Therefore, Avi will reach a maximum height of 9 meters.

6 0
3 years ago
A block is attached to a horizontal spring. On top of this block rests another block. The two-block system slides back and forth
Minchanka [31]

Answer:

Angular frequency will increase

No change in the amplitude

Explanation:

At extreme end of the SHM the energy of the SHM is given by

E = \frac{1}{2} (m_1 + m_2)\omega^2 A^2

here we know that

\omega^2 = \frac{k}{m_1 + m_2}

now at the extreme end when one of the mass is removed from it

then in that case the angular frequency will change

\omega'^2 = \frac{k}{m_1}

So angular frequency will increase

but the position of extreme end will not change as it is given here that the top block is removed without disturbing the lower block

so here no change in the amplitude

6 0
3 years ago
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