Question

The table shows a set of values for x and y

Answer 1

a) Assume y = $x^{2}$

$1b=\frac{k}{1^{2} }$ k = 1b

$y=\frac{1b}{x^{2} }$

b) y = 25

$x^{2}=\frac{16}{25}$

$x=\sqrt{\frac{4}{5} ^{2} }$

x = ±$\frac{4}{5}$

x > 0, x = 4/5

{ Equation }