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Harlamova29_29 [7]
2 years ago
15

car starts from rest and reaches a velocity of 10 m/s in 10s a) Draw the v against t graph for the motion of the car? b) From th

e graph find: i) the slope of the graph. II) Area of the v against t graph bounded by the slope, on x-axis. c) What are the slope and area of v against t graph equal to respectively?​
Physics
2 answers:
Natali [406]2 years ago
8 0

Answer:

The above answer is correct too, keep busy

kirza4 [7]2 years ago
6 0

Explanation:

여기 당신의 대답이 있습니다. 즐겨 . 팔로우하고 브레인리스트로 표시해주세요

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+2 electron charges = 2x1.6x10^-19Coulombs

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2 years ago
A mass spectrometer was used in the discovery of the electron. In the velocity selector, the electric and magnetic fields are se
Mama L [17]

Answer:

Explanation:

Radius of dee, r = 8 mm = 0.008 m

Electric field, e = 400 V/m

Magnetic field, B = 4.7 x 10^-4 T

mass of electron, m = 9.1 x 10^-31 kg

charge of electron, q = 1.6 x 10^-19 C

(a) Let v is the speed of electrons.

v = \frac{Bqr}{m}

v = \frac{4.7\times 10^{-4}\times 1.6\times 10^{-19}\times 0.008}{9.1 \times 10^{-31}}

v = 661098.9 = 661099 m/s

(b)

\frac{e}{m}=\frac{1.6 \times 10^{-19}}{9.1\times 10^{-31}}

e / m = 1.76 x 10^14 C / kg

(c) Let K be the kinetic energy

K = 0.5 x mv²

K = 0.5 x 9.1 x 10^-31 x 661099 x 661099

K = 1.99 x 10^-19 J

K = 1.24 eV

So, the potential difference is

V = 1.24 V

(d) if the acceleration voltage is doubled

V = 2 x 1.24 = 2.48 V

So, Kinetic energy

K = 2.48 eV

K = 2.48 x 1.6 x 10^-19 = 3.968 x 10^-19 J

Let v is the speed

K = 0.5 x mv²

3.968 x 10^-19 = 0.5 x 9.1 x 10^-31 x v²

v = 933856.5 m/s

Let the new radius is r.

r=\frac{mv}{Bq}

r=\frac{9.1\times 10^{-31}\times 933856.5}{4.7\times 10^{-4}\times 1.6\times 10^{-19}}

r = 0.0113 m = 1.13 cm

7 0
3 years ago
Two waiters are trying to get through a single door of a kitchen. One pushes on one side of a door 0.567 m from the hinge with a
NISA [10]

Answer:

275.5 N

Explanation:

F_{1} = Force on one side of the door by first waiter = 257 N

F_{2} = Force on other side of the door by second waiter

r_{1} = distance of first force by first waiter from hinge = 0.567 m

r_{2} = distance of second force by second waiter from hinge = 0.529 m

Since the door does not move. hence the door is in equilibrium

Using equilibrium of torque by force applied by each waiter

r_{1} F_{1} = r_{2} F_{2} \\(0.567) (257) = (0.529) F_{2}\\F_{2} = 275.5 N

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