The photosynthesis equation is :
H2O + CO2 + sunlight (energy) > C6H12O6 + O2
So water (H2O) and carbon dioxide (CO2) are the raw materials need for photosynthesis.
The radio waves have a very low frequency so they will always have a very low energy.
Good luck :)
Time taken to reach water :
Now, initial vertical speed , u = 0 m/s.
By equation of motion :
Here, a = g = acceleration due to gravity = 9.8 m/s².
So,
Therefore, the height of the bridge is 3.46 m.
Hence, this is the required solution.
So first Identify all the given Varibales so u can choose which Eqauton to use
D=200m
T=4s
Vi=10m/s
Vf=?
You should this equation
D= 0.50(Vf+Vi)T
Plug in the values
200= 0.50 (Vf+10) 4
Divide the 4 out of the right side and if you do sumthing to one side you gotta do it to the other
200 divided by 4= 0.50(Vf+10)
50= 0.50(Vf+10)
Now expand the 0.50
So 50= 0.5Vf + 5 (because 0.5 times 10 is 5)
Now get rid of the 5
50-5= 0.5Vf
45 =0.5Vf now Divide the 0.5 out
45 divided by 0.5 = Vf
And 45/0.5 is 90
So 90=Vf
Therefore the final Velocity is 90m/s
Answer:
v_f = -25.9 m/s
Explanation:
- The complete question is as follows:
" Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. Define the direction the pitcher originally throws the ball as the +x direction.
Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of −8.4N⋅s to the baseball?"
Given:
- mass of baseball m = 0.145 kg
- Speed before impact v_i = 32 m/s
- Speed after impact v_f
- Impulse applied by the bat I = - 8.4Ns
Find:
What is the ball's velocity just after leaving the bat
Solution:
- Impulse is the change in linear momentum of the ball according to Newton's second law of motion:
I = m* ( v_f - v_i )
- Taking the + from pitcher to batsman and - from batsman to pitcher.
- Plug in the values:
-8.4 = 0.145* ( v_f - (32) )
v_f = -57.93103 + 32
v_f = -25.9 m/s
