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Artyom0805 [142]
2 years ago
6

A sample of chlorine gas is stored at a temperature of -25oC. If the chlorine gas's temperature is raised to 52oC, its volume in

creases to 2.60 L. What is the initial volume of the gas?
Chemistry
1 answer:
aalyn [17]2 years ago
4 0

Answer:

whats ur answer options

Explanation:

...

its b

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Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the s
True [87]

Answer:

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

Explanation:

Yo know the following balanced reaction:

CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)

You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:

  • CuSO₄: 1 mole
  • Zn: 1 mole
  • Cu: 1 mole
  • ZnSO₄: 1 mole

Being:

  • Cu: 63.54 g/mole
  • S: 32 g/mole
  • O: 16 g/mole
  • Zn: 65.37 g/mole

the molar mass of the compounds participating in the reaction is:

  • CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
  • Zn: 65.37 g/mole
  • Cu: 63.54 g/mole
  • ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:

  • CuSO₄: 1 moles* 160 g/mole= 160 g
  • Zn: 1 mole* 65.37 g/mole= 65.37 g
  • Cu: 1 mole* 63.54 g/mole= 63.54 g
  • ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g

Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

mass of Zn=\frac{454 grams of CuSO_{4} *65.37 grams of Zn}{160 grams of CuSO_{4}}

mass of Zn= 185.49 grams

<u><em>185.49 grams of Zinc would react with 454g (1lb) of copper sulfate</em></u>

4 0
3 years ago
Data Table 3: Polystyrene Test Tube, 12x75mm
Lera25 [3.4K]

Answer:

Experiment 8 E Data Table 3 fl Data Table 4 fl Data Table 5 fl Data Table 6 Data Table 3: Polystyrene Test Tube, 12x75mm Volume of water at room temperature (V1 in mL) Volume of gas in polystyrene tube at boil (V2 in mL) Temperature of gas at boil inside polystyrene tube (°C) Volume of gas in polystyrenetube at room temperature (V3 in mL) Temperature of gas.

Explanation:

Hope this helps

Mark as Brainliest please

4 0
2 years ago
How many moles of solute would be dissolved in .500 kg of solvent to make a 2.50 molal NaOH solution?
Tom [10]

Molality is a measure of concentration that relates the moles of solute to the kilograms of solvent, it is described by the following equation:

Molality=\frac{molSolute}{kgSolvent}

We are given the molality(2.50m) and kilograms of solvent(0.500kg), so we solve for moles of solute from the equation:

molSolute=Molality\times kgSolvent\begin{gathered} molSolute=2.50m\times0.500kg \\ molSolute=1.25molSolute \end{gathered}

To make a 2.50molal NaOH solution would be needed 1.25moles of solute

Answer: 1.25 moles

3 0
1 year ago
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --&gt; 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
2 years ago
When naming bases, you add ___ to the end
dangina [55]

Answer:

hydroxide ion

Explanation:

because base produce hydroxide ion when dissolved in water

6 0
2 years ago
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