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Artyom0805 [142]
3 years ago
6

A sample of chlorine gas is stored at a temperature of -25oC. If the chlorine gas's temperature is raised to 52oC, its volume in

creases to 2.60 L. What is the initial volume of the gas?
Chemistry
1 answer:
aalyn [17]3 years ago
4 0

Answer:

whats ur answer options

Explanation:

...

its b

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Which statement is correct for the element of proton number 19?
BlackZzzverrR [31]

Answer:

D

Explanation:

From periodic table : proton number 19  corresponds to K  (potassium)

  which is very reactive with water

8 0
2 years ago
Find the mass of 3.89 mol of NaF​
Otrada [13]
The answer is 163.333993748 grams
3 0
3 years ago
instrucions classify the following reactions as synthesis, decomposition,single replacement, double replacement, or combustion.
My name is Ann [436]

Answer:

There are no specific equations but here what i can give you:

1. Synthesis -- A synthesis reaction is a chemical change in which two or more substances react to form a single new substance.

In all synthesis reactions, there is a single product that is a compound!

2. Decomposition -- A decomposition reaction is a chemical change in which a single compound breaks down into two or more simpler products. (This is the opposite of synthesis reactions!)

Most decomposition reactions require energy in the form of heat, light, and electricity.

3. Single Replacement -- A single-replacement reaction is a chemical change in which one element replaces a second element in a compound. You can identify a single-replacement reaction by noting that both the reactants and the products consist of an element and a compound.

4. Double Replacement -- A double-replacement reaction is a chemical change involving an exchange of positive ions between two compounds.

For a double replacement reactions to occur, one of the following is usually true:

- One of the products is only slightly soluble and precipitates from solutions.

- One of the products is a gas.

- One product is a molecular compound such as water.

5. Combustion -- A combustion reactions is a chemical change in which an element or a compound reacts with oxygen, often producing energy in the form of heat or light.

A combustion reactant always involves oxygen as a reactant. (If the supply of oxygen is limited, then the combustion will not be complete.)

The other reactant is a hydrocarbon, which is a compound composed of hydrogen and carbon and the complete combustion of a hydrocarbon produces CO2 and H2O.

Hydrocarbons include methane, propane, and butane.

I really hope this helps you!

3 0
3 years ago
Three 1.0-l flasks, maintained at 308 k, are connected to each other with stopcocks. initially the stopcocks are closed. one of
Licemer1 [7]

Answer:

0.6103 atm.

Explanation:

  • We need to calculate the vapor pressure of each component after the stopcocks are opened.
  • Volume after the stopcocks are opened = 3.0 L.

<u><em>1) For N₂:</em></u>

P₁V₁ = P₂V₂

P₁ = 1.5 atm & V₁ = 1.0 L & V₂ = 3.0 L.

P₂ of N₂ = P₁V₁ / V₂ = (1.5 atm) (1.0 L) / (3.0 L) = 0.5 atm.

<u><em>2) For H₂O:</em></u>

Pressure of water at 308 K is 42.0 mmHg.

we need to convert from mmHg to atm: <em>(1.0 atm = 760.0 mmHg)</em>.

P of H₂O = (1.0 atm x 42.0 mmHg) / (760.0 mmHg) = 0.0553 atm.

We must check if more 2.2 g of water is evaporated,

n = PV/RT = (0.0553 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.00656 mole.

m = n x cmolar mass = (0.00656 mole) (18.0 g/mole) = 0.118 g.

It is lower than the mass of water in the flask (2.2 g).

<em><u>3) For C₂H₅OH:</u></em>

Pressure of C₂H₅OH at 308 K is 102.0 mmHg.

we need to convert from mmHg to atm: (1.0 atm = 760.0 mmHg).

P of C₂H₅OH = (1.0 atm x 102.0 mmHg) / (760.0 mmHg) = 0.13421 atm.

We must check if more 0.3 g of C₂H₅OH is evaporated,

n = PV/RT = (0.13421 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.01594 mole.

m = n x molar mass = (0.01594 mole) (46.07 g/mole) = 0.7344 g.

<em>It is more than the amount in the flask (0.3 g), so the pressure should be less than 0.13421 atm.</em>

We have n = mass / molar mass = (0.30 g) / (46.07 g/mole) = 0.00651 mole.

So, P of C₂H₅OH = nRT / V = (0.00651 mole) (0.082 L.atm/mole.K) (308.0 K) / (3.0 L) = 0.055 atm.

  • <em>So, </em><em>total pressure</em><em> = </em><em>P of N₂ + P of H₂O + P of C₂H₅OH</em><em> = 0.5 atm + 0.0553 atm + 0.055 atm = </em><em>0.6103 atm</em><em>.</em>
3 0
3 years ago
Calculate the ph of a solution in which [oh–] = 4.5 × 10–9m.
frosja888 [35]

pOH = -LOG([OH])  

pOH = -LOG(4.5*10^-9)  

pOH = 8.34  

pH + pOH = 14  

pH = 14 - 8.34 = 5.65

hope this helps!

(:

5 0
3 years ago
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