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QveST [7]
3 years ago
6

What is the net amount of energy released when one mole of h2o(?) is produced?

Chemistry
1 answer:
german3 years ago
7 0
The net amount of energy produced can be obtained from a table of enthalpy change of formation, available online.

The enthalpy change of formation indicate how much energy the 1 mole of the product (H2O) has relative to the elemental reactants (H2 and O2).  In other words, the "lost" energy equals the heat/energy released. 

For water (H2O), this value is -285.8 if the final product is a liquid under standard conditions, and -241.82 if the product is in gas form which contains some energy that could be further released.  This means that if the final product (H2O) is in liquid form, energy released is 285.8 kJ/mol.

Since water is in liquid form under standard conditions, the first value (285.8 kJ/mol) is generally appropriate.
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Answer:

The Correct increasing order of solubility is O2 < Br2 < LiCl < Methanol (CH3OH)

Explanation:

Solubility of compounds or molecules are solely dependent on its inter molecular forces or bonding present in them.

Molecules with Hydrogen bonding usually very soluble in water. Ionic compounds are also very soluble in water because they form ions in solutions. Molecules that possess van der waal forces are usually insoluble in water because they are non-polar.

  • O2 (oxygen gas) and Br2 (bromine gas) have van der waal forces in them. Van der waal forces are stronger in Br2 (bromine gas) than O2 (oxygen gas) because Br2 has more number of electrons.
  • LiCl is ionic in nature which makes it dissolve in water readily. it easily forms its ions (Li+ and Cl- ) in solutions.
  • Methanol (CH3OH) has the highest solubility in water compared to LiCl, Br2 and O2 because it contains Hydrogen bonding which is strongest of all inter molecular forces.  

4 0
3 years ago
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Gekata [30.6K]

Hey, the two answers that would best fit in the blank would be B.) reproduce by mitosis & D.) Have 46 chromosome pairs.


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5 0
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Substituting the known variables,
 
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Solving for V1 gives an answer of V1 = 2 L. Thus, to prepare the needed solution, dilute 2 L of 6.0 M H2SO4 solution with water until the volume reach 4.8 L. 


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3 years ago
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