5. All the resistors in this circuit, the 18 Ω resistor included, are in parallel. The voltage drop across each resistor is the same, which is the equivalent to the potential difference of the battery. That is, 36 V [choice K].
6. The ammeter is in series with the branch containing a 12 Ω resistor. Since the voltage drop across this resistor is 36 V, the current in this branch will be I = V/R = (36 V)/(12 Ω) = 3.0 A [choice D].
7. The equivalent resistance of the circuit can be calculated as follows:
1/R = 1/12 + 1/9 + 1/18 = 1/4; thus, R = 4.0 Ω [choice G].
8. Electrical power can be defined as electrical work/time, and electrical work can be given by W = qV. If P = qV/t and q/t = I (charge flowing per unit time is equal to current), then P = VI. From Ohm's law, V = IR, and I = V/R. Substituting V/R for I in the power equation, P = V²/R.
For this circuit, the V = 36 V and R (the equivalent resistance) = 4.0 Ω. So, the power loss in the circuit is P = (36 V)²/(4.0 Ω) = 324 W [choice J].
Answer:
is the current through the body of the man.
energy dissipated.
Explanation:
Given:
- time for which the current lasted,
- potential difference between the feet,
- resistance between the feet,
<u>Now, from the Ohm's law we have:</u>
is the current through the body of the man.
<u>Energy dissipated in the body:</u>
Answer:
The answer to your question is: F = 0.4375 N. The force will be 16 times lower than with the first conditions.
Explanation:
Data
F = 7 N
F = ? if the masses is quartered
Formula
Process
Normal conditions F = Km₁m₂/r² = 7
When masses quartered F = K(m₁/4)(m₂/4)/r² = ?
F = K(m₁m₂/16)/r²
F = K(m₁m₂/16r² = 7/16 = 0.4375 N
Answer it is b is the best option to pick A, does that make sense
90 degrees - 30 = 60 degrees
Velocity = (5m/s - 4.35m/s x cos(30)) / cos(60)
Velocity = 2.47 m/s
The answer is D) 2.47 m/s at 61.9 degrees
