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3 years ago

Check cashing businesses do not require that an individual be an account holder; they will cash any valid check. True False

Physics

2 answers:

ANEK [815]3 years ago

4 0

Answer:

True.

Explanation:

Check cashing businesses provide customers with an easy way to turn their checks into cash without having to rely on a bank account.

These types of businesses will cash any valid check, not prior scrutinize the check-in different ways to avoid fraudulent transactions and possible scams. Once the employee oversees the check it would tell the customer how much they´ll give in cash and what they´ll charge in fees.

I hope this answer helps you.

Romashka-Z-Leto [24]3 years ago

3 0

True. Free trade means they can't refuse to give you cash for a check. If you want the check deposited to an account, that's another story.

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A driver slammed on her brakes and came to a stop with constant acceleration. Measurements on her tires and skid marks on the pa

IRISSAK [1]

Answer:

u = 29.22 m/s

Explanation:

distance (s) = 58.52 m

coefficient of kinetic friction (k) = 0.75

final velocity (v) = 0 m/s

acceleration due to gravity (g) = 9.8 m/s^{2}

How fast was she driving (u)

we can get how fast she was driving by using the formula below

s = ut - $\frac{1}{2}.at^{2}$ ...equation 1

where

s = distance
u = her initial velocity
a = acceleration = $\frac{f}{m} = \frac{kmg}{m} = kg$

k = coefficient of kinetic friction
g = acceleration due to gravity

t = time

from v = u - at (recall that v = 0)

0 = u - at, therefore t = u/a = u/kg

now substituting the required values above into equation 1 we have

s = $\frac{u^{2}}{kg} - \frac{u^{2}}{2kg}$

s = $\frac{u^{2}}{2kg}$

u = $\sqrt{2kgs}$

u = $\sqrt{2 x 0.75 x 9.8 x 58.52}$

u = 29.22 m/s

8 0

3 years ago

Help pleasseeee URGENT

Zina [86]

Answer:

The speed of the 8-ball is 2.125 m/s after the collision.

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total momentum of a system of masses is conserved unless an external force is applied. The momentum of a body with mass m and velocity v is calculated as follows:

P=mv

If we have a system of masses, then the total momentum is the sum of all the individual momentums:

$P=m_1v_1+m_2v_2+...+m_nv_n$

When a collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, the law of conservation of linear momentum is simplified to:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.

After the collision, the cue ball comes to rest v2'=0. It's required to find the final speed v1' after the collision.

The above equation is solved for v1':

$\displaystyle v'_1=\frac{m_1v_1+m_2v_2-m_2v'_2}{m_1}$

$\displaystyle v'_1=\frac{0.16*0+0.17*2-0.17*0}{0.16}$

$\displaystyle v'_1=\frac{0.34}{0.16}$

$v'_1=2.125\ m/s$

The speed of the 8-ball is 2.125 m/s after the collision.

8 0

3 years ago

A book weighing 5 N rests on top of a table. 1) A downward force of magnitude 5 N is exerted on the book by the force of

andreev551 [17]

Answer:

1) A downward force of magnitude 5 N is exerted on the book by the force of of gravity

2) An upward force of magnitude 5 N is exerted on the book by the table

Explanation:

First of all, any object near the Earth's surface experiences the forces of gravity, which is also called weight of the object. This force always acts downward.

For the book in the problem, the magnitude of the weight is 5 N.

We also know that the book is at rest: this means that the net force acting on it is zero, and there must be another force balancing the weight, in order to give a zero net force. This other force is the reaction force exerted by the table on the book: the magnitude of this force must be equal to the force of gravity (so, 5 N) and its direction is opposite to the weight, therefore upward.

7 0

3 years ago

Problem 1: Two sources emit waves that are coherent, in phase, and have wavelengths of 26.0 m. Do the waves interfere constructi

Anton [14]

1) Destructive interference

The condition for constructive interference to occur is:

$\delta = m\lambda$ (1)