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3 years ago

How many moles are present in 1.75 moles of dihydrogen monoxide, H2O?

Chemistry

1 answer:

KATRIN_1 [288]3 years ago

5 0

Answer:

31.5 grams

Explanation:

I'm guessing you meant how many grams are in 1.75 moles of H2O

You need a periodic table for this first you're going to find the atomic mass for Hydrogen (1.008) and oxygen (15.999)

since there are 2 Hydrogen in the problem you'll multiply 1.008 by 2 giving you 2.016

You'll then add your 1 Nitrogen to this to get 18.015: this number is the grams for 1 mole of H2O, you'll then multiply 18.015 by 1.75 to find the grams for that many moles (31.52625) this is how many grams are in 1.75 moles of H2O

Don't forget sig figs though so your answer will be 31.5

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anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

$K_a\times K_b=K_w$

$K_b$ for sodium formate is $K_b=\frac {K_w}{K_a}$

Given that:

$K_a$ of formic acid = $1.8\times 10^{-4}$

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Consider the ICE take for the formate ion as:

HCOO⁻ + H₂O ⇄ HCOOH + OH⁻

At t=0 0.35 - -

At t =equilibrium (0.35-x) x x

The expression for dissociation constant of sodium formate is:

$K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}$

$5.5556\times 10^{-11}=\frac {x^2}{0.35-x}$

Solving for x, we get:

x = 0.44×10⁻⁵ M

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