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vladimir1956 [14]
3 years ago
9

How many moles are present in 1.75 moles of dihydrogen monoxide, H2O?

Chemistry
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

31.5 grams

Explanation:

I'm guessing you meant how many grams are in 1.75 moles of H2O

You need a periodic table for this first you're going to find the atomic mass for Hydrogen (1.008) and oxygen (15.999)

since there are 2 Hydrogen in the problem you'll multiply 1.008 by 2 giving you 2.016

You'll then add your 1 Nitrogen to this to get 18.015: this number is the grams for 1 mole of H2O, you'll then multiply 18.015 by 1.75 to find the grams for that many moles (31.52625) this is how many grams are in 1.75 moles of H2O

Don't forget sig figs though so your answer will be 31.5

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What mass of ammonia can be produced if 13.4 grams of nitrogen gas reacted ?
aivan3 [116]

Answer:

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 13.4 grams

Molar mass of N2 = 28 g/mol

Molar mass of NH3 = 17.03 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles of N2

Moles N2 = Mass N2 / molar mass N2

Moles N2 = 13.4 grams / 28.00 g/mol

Moles N2 = 0.479 moles

Step 4: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles

Step 5: Calculate mass of NH3

Mass of NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.958 moles * 17.03 g/mol

Mass NH3 = 16.3 grams

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

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3 years ago
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Answer:

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Explanation:

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