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son4ous [18]
3 years ago
12

Only two stable isotopes of chlorine exist. 35Cl has a mass of 34.96885 amu and 37Cl has a mass of 36.9659 amu. Given that the a

tomic mass of chlorine is 35.453, calculate the isotopic abundance of 37Cl. (Enter your answer as a decimal number between zero and one.)
Chemistry
1 answer:
ivann1987 [24]3 years ago
3 0

Answer: The isotopic abundance of Cl- 37 is 0.2424.

Explanation:

Mass of isotope - 35 = 34.96885 amu

% abundance of isotope -35= x% = \frac{x}{100}

Mass of isotope - 37 = 36.9659 amu.

% abundance of isotope-37 = (100-x)% = \frac{100-x}{100}

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

35.453=\sum[(34.96885 \times \frac{x}{100})+(36.9659 \times \frac{100-x}{100}]]

x=75.76\%

(100-75.76)=24.24\%=0.2424

Therefore,  the isotopic abundance of Cl- 37 is 0.2424.

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Answer:

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Explanation:

From

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8 0
3 years ago
Jaiden is writing a report about the structure of the atom. In her report, she says that the atom has three main parts and two s
yulyashka [42]

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2 years ago
An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
aleksley [76]

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Let's first take account of what we have and convert them into the correct units.

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Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

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Let's look back at MM= \frac{m}{n} and plug in what we know.

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