Answer:
T’= 4/3 T
The new tension is 4/3 = 1.33 of the previous tension the answer e
Explanation:
For this problem let's use Newton's second law applied to each body
Body A
X axis
T = m_A a
Axis y
N- W_A = 0
Body B
Vertical axis
W_B - T = m_B a
In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension
We write the equations
T = m_A a
W_B –T = M_B a
We solve this system of equations
m_B g = (m_A + m_B) a
a = m_B / (m_A + m_B) g
In this initial case
m_A = M
m_B = M
a = M / (1 + 1) M g
a = ½ g
Let's find the tension
T = m_A a
T = M ½ g
T = ½ M g
Now we change the mass of the second block
m_B = 2M
a = 2M / (1 + 2) M g
a = 2/3 g
We seek tension for this case
T’= m_A a
T’= M 2/3 g
Let's look for the relationship between the tensions of the two cases
T’/ T = 2/3 M g / (½ M g)
T’/ T = 4/3
T’= 4/3 T
The new tension is 4/3 = 1.33 of the previous tension the answer e
Explanation:
answer is the 3rd law of motion
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Answer:
Bob provided the greatest impulse.
Explanation:
Given:
Arnold exerts force = 300 N for 3 seconds
Bob exerts force = 500 N for 2 seconds
Cecil exerts force = 200 N for 4 seconds.
Find:
Highest impulse
Computation:
Impulse = Force × TIme
Arnold provides impulse = 300 N × 3 seconds = 900 N/s
Bob provides impulse = 500 N × 2 seconds = 1,000 N/s
Cecil provides impulse = 200 N × 4 seconds = 800 N/s
Therefore, Bob provided the greatest impulse.
T=s/v=>t=1500/1,5=1000s
1,5km=1500m
Answer: A - a gap on each side of the clutch disk facing when disengaged
Explanation:
A clutch switch is used to ensure the clutch is disengaged
or Prevent the engine from starting unless the clutch pedal is depressed
When a clutch is disengageda gap will be on each side of the facing.
