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Paul [167]
3 years ago
9

Electromagnetic radiation can be specified by its wavelength ( ), its frequency ( ) or its period ( ). The period is the time it

takes one complete wavelength to pass a point in space. Based on this information, what is the mathematical relationship between and ?
Physics
1 answer:
kirill [66]3 years ago
3 0

Answer:

The relation between f,T,λ

f=\frac{1}{T}

λ =\frac{v}{f}

λ =\frac{v}{T}

Explanation:

Let us consider,

                         wavelength as λ

                             frequency as  f

                             time period as T

The <em>time period</em> is defined as time taken by the wave to complete one oscillation or number or seconds to complete one full oscillation.

The <em>frequency </em>is defined as number of oscillation done per second.

The <em>wavelength</em> is defined as distance between two successive crests or trough. in a wave.

<em>The frequency and time period are reciprocals. </em>

<em>The wavelength and frequency are reciprocals ie larger the wavelength shorter is the frequency</em>

The relation between frequency and time period is f =\frac{1}{T}.

The relation between wavelength and frequency is λ =\frac{v}{f}

                     where v is velocity of light.

The relation between wavelength and time period is λ =\frac{v}{T}

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Someone is trying to balance a (110cm) plank with certain forces.
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Answer:

a. i. 30 Nm ii. This moment is a clockwise positive moment.

b. i. 15 Nm ii, This moment is a counter-clockwise negative moment.

c. i. The plank will not balance. ii. The plank would tip up.

d. 150 N

Explanation:

a) Calculate the moment of the 60N force (about O), then name its type.

i. Calculate the moment of the 60N force (about O)

Since moment = Force × perpendicular distance from point of moment ,

M = Fd

Since F = 60 N and d = 50 cm = 0.5 m

M = 60 N × 0.5 m = 30 Nm

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This moment is a clockwise positive moment.

b) Calculate the moment of the 30N force (about O), then name its type.

i. Calculate the moment of the 30N force (about O),

Since moment = Force × perpendicular distance from point of moment ,

M' = F'd'

Since F' = 30 N and d' = 50 cm = 0.5 m

M' = 30 N × 0.5 m = 15 Nm

ii. Then name its type.

This moment is a counter-clockwise negative moment.

c) Will the plank balance? If not, which way will it tip?

i. Will the plank balance?

The plank will balance if the net moment on it is zero

So net moment, M' = positive moment - negative moment = M - M' = 30 Nm   - 15 Nm = 15 Nm

Since the net moment on the plank is M" = 15 Nm ≠ 0,<u>the plank will not balance.</u>

ii Which way will it tip?

The plank would tip in the direction of the greater moment since the net moment is positive. <u>This moment tilts the plank in a clockwise direction, so the plank would tip up.</u>

d) What extra force would be needed at (B) to balance the plank?

The extra force must balance the net moment,

So M" = F"d" where F" = force and d" = distance of force from O = 10 cm = 0.10 m

F" = M"/d"

= 15 Nm/0.10 m

= 150 N

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Answer:

by answering your question

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