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vivado [14]
3 years ago
11

Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica? t

he force that the ball exerts on the wall the frictional force between the wall and the ball the acceleration of the ball as it approaches the wall the normal force that the wall exerts on the ball
Physics
2 answers:
Leona [35]3 years ago
7 0

actually the answer is D.

:)

Nutka1998 [239]3 years ago
6 0

Answer:

the normal force that the wall exerts on the ball

Explanation:

As Newton's third law states:

"when an object A exerts a force on object B, then object B exerts an equal and opposite force on object A".

If we apply this law to this problem, we can identify the ball as object A, and the wall as object B. As the ball hits the wall, the ball exerts a force on the wall (toward the direction of motion of the ball), so the wall exerts an equal and opposite force on the ball (in the opposite direction). This force is the normal force of the wall, and it is responsible for pushing the ball back towards Erica.

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jenyasd209 [6]

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2 years ago
A table tennis ball with a mass of 0.003 kg and a soccer ball with a mass of 0.43 kg or both Serta name motion at 16 M/S calcula
poizon [28]
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8 0
3 years ago
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Two marbles, one twice as heavy as the other, are dropped to the ground from the roof of a building. Just before hitting the gro
Andreyy89

Answer:

 B. twice as much kinetic energy

Explanation:

Lets take the mass of the first marble =2 m

the mass of the second marble = m

We know that velocity of particle does not depends on their mass that is the velocity of both mass will be same after dropping from the roof.

We know that kinetic energy of a mass is given as

KE=\dfrac{1}{2}Mv^2

Kinetic energy for heavier mass

KE=\dfrac{1}{2}\times 2m\times V^2

Kinetic energy for light mass

KE'=\dfrac{1}{2}\times m\times V^2

KE=2 KE '

Form above two equation we can say that ,the kinetic energy for the heavier mass is twice the lighter mass.

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7 0
3 years ago
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Darya [45]

Answer:

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v=\sqrt{(5.49)^2-2\times2.244\times3.89}

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