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vivado [14]
3 years ago
11

Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica? t

he force that the ball exerts on the wall the frictional force between the wall and the ball the acceleration of the ball as it approaches the wall the normal force that the wall exerts on the ball
Physics
2 answers:
Leona [35]3 years ago
7 0

actually the answer is D.

:)

Nutka1998 [239]3 years ago
6 0

Answer:

the normal force that the wall exerts on the ball

Explanation:

As Newton's third law states:

"when an object A exerts a force on object B, then object B exerts an equal and opposite force on object A".

If we apply this law to this problem, we can identify the ball as object A, and the wall as object B. As the ball hits the wall, the ball exerts a force on the wall (toward the direction of motion of the ball), so the wall exerts an equal and opposite force on the ball (in the opposite direction). This force is the normal force of the wall, and it is responsible for pushing the ball back towards Erica.

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During crystallisation the crystals separate out from the hot ________solution of a substance on cooling
alekssr [168]

Answer:

The process of separation or deposition of crystals from a hot saturated solution on gentle cooling of the solution is called 'crystallisation'.

Explanation:

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2 years ago
If a car speeds up and pushes back on the road, what does the road do to the car?
Basile [38]

Answer:

make it go faster

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3 years ago
Two of the types of infrared light, ir-c and ir-a, are both components of sunlight. their wavelengths range from 3000 to 1,000,0
NikAS [45]
The energy of a light wave is calculated using the formula
E = hc/λ
h is the Planck's constant
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For the ir-a, the range is
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6 0
3 years ago
Read 2 more answers
I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t
dezoksy [38]
Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where L is the length of the string, T the tension and m its mass. If  we plug the data of the problem into the equation, we find
f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz

The wavelength of the standing wave is instead twice the length of the string:
\lambda=2 L= 2 \cdot 24 m=48 m

So the speed of the wave is
v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
t= \frac{L}{v}= \frac{24 m}{69.1 m/s}=0.35 s
7 0
3 years ago
How to convert work done in joules into kilojoules?
Sav [38]

1 Kilojoule [kJ] = 737.562 149 277 27 Foot pound force [ftlbf]

3 0
1 year ago
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