Answer:
1.0416 m∧3/sec
Explanation:
check the pictures below for the solution
Answer:
A ) 1000 m.
Explanation:
Here initial velocity u = 100 m /s
Final velocity v = 0
Acceleration a = -5 ms⁻²
Distance travelled = S
v² = u² + 2aS
0 = (100)² -2 x 5 S
S = 10000/ 10
=1000 m.
The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours
<h3>What is time?</h3>
Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)
To get the time that was saved on the 8.6-mile trip, we use the formula below.
Formula:
- Ts = (d/v₁)-(d/v₂)................. Equation 1.
Where:
- Ts = Time saved on the trip
- d = distance covered during the trip
- v₁ = Initial legal speed limit
- v₂ = final/current legal speed limit.
From the question,
Given:
- d = 86.0 mile
- v₁ = 55.0 mi/h
- v₂ = 75.0 mi/h
Substitute these values into equation 1
- Ts = (86/55)-(86/75)
- Ts = 1.564-1.147
- Ts = 0.42 h.
Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.
Learn more about time here: brainly.com/question/13893070
Answer:
i=1250000000Nm
ii=50000m/s
Explanation:
energy=force ×distance
500000N×(2.5×1000)m
=1250000000Nm
ii. Force=mass ×acceleration
500000N =40000kg ×a
500000 ÷40000=12.5a
s=1/2at^2
2500m=1/2×12.5×t^2
2500m=6.25×t^s
2500÷6.25=400
t^2=400
√t^2=√400
t=20seconds
speed=distance ×time taken
=2500m × 20s
=50000m/s