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jok3333 [9.3K]
3 years ago
15

A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavele

ngths of visible light is strongly reflected?
Physics
1 answer:
iren [92.7K]3 years ago
6 0

Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, n=1.35.

The thickness of the soap bubble wall is, t=300 nm.

Now, for constructive interference of soap bubble.

2nt=(m+\frac{1}{2})\lambda.

Now for first order m=1.

Therfore,

\lambda =\frac{4}{3} tn

Substitute all the variables in the above equation.

\lambda =\frac{4}{3} (1.35)(300 nm).

Therefore,

\lambda =540 nm.

Therefore the visible light wavelength which is strongly reflected is 540 nm.

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Ice is water in solid phase, in this phase, the particles are very close together and relatively in fixed positions.

As the temperature starts to increase (thermal energy), also does the kinetic energy of the particles (so we have a change from thermal energy to kinetic energy), so they start to move "more", and the position of the particles starts to be less "fixed". There is a point where the particles have enough energy, and this point is where the phase of the water changes from solid to liquid phase (the fusion point). After this point the water can not hold his shape, and takes the shape of the container where it is.

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The electrons making the shock come from the women's body.

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1 year ago
A fish can travel 30km/h in still water. How long will it take to arrive 12km downstream in a river flowing 6km/h?
kodGreya [7K]
30 + 6 = 36

36/12 = 3



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3 years ago
A projectile is shot on level ground with a
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Answer:

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Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

theta = 63.4 deg

2 theta = 126.9 deg

sin 126.9 = .8

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R = 1445 * .8 / 9.8 = 118 m    agreeing with answer found above

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2 years ago
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