Answer:
x-intercept is (13/3, 0)
y-intercept is (0,-13)
Step-by-step explanation:
change y+1 = 3(x-4) into slope-intercept form:
y+1 = 3x-12
y = 3x-13
y-intercept is (0,-13)
to get x-intercept, plug zero in for 'y' and solve for 'x':
0 = 3x-13
13 = 3x
13/3 = x
x-intercept is (13/3, 0)
Answer:
4t³-5t²+2t+200 - (3t³-2t²+5t+100) = t³-3t³-3t+100
Step-by-step explanation:
Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
Answer:
A Circle
Step-by-step explanation: