Answer:
There are seven seventh roots of unity, e2πki7 , all on the unit circle, r=1 above.
The first one is at θ=2π7=360∘7=5137 ∘ , and there are others at 4π7,6π7,8π7,10π7,12π7 and of course at 0 radians, i.e. unity itself.
How to find?
There are 4 fourth roots of unity and they are 1, i,−1 and−i
Each of the roots of unity can be found by changing the value of k k k in the expression e 2 k π i / n e^{2k\pi i/n} e2kπi/n. By Euler's formula, e 2 π i = cos ( 2 π ) + i sin ( 2 π ) = 1.
Answer:
Step-by-step explanation:
Students are asked to write 
in the standard form.
Now, in the standard form of a polynomial the highest power of the variable takes the leftmost position and the lowest power of the variable takes the rightmost position and the power of variable decreases from left to right.
Therefore, the standard form will be . (Answer)
Answer:
Value of w = 6
Step-by-step explanation:
Given:
AB= 4w-4
BC = 2w-8
AC = 24
Find:
Value of w
Computation:
AB + BC = AC
4w - 4 + 2w - 8 = 24
6w - 12 = 24
6w = 24 + 12
6w = 36
w = 6
Value of w = 6
sin(α) = ⁻⁵/₁₃
sin⁻¹[sin(α)] = sin⁻¹(⁻⁵/₁₃)
α ≈ 1.1256π
cos(β) = ²/₅
cos⁻¹[cos(β)] = cos⁻¹(²/₅)
β ≈ 1.6311π
sin(α - β) = sin(1.1256π - 1.6311π)
sin(α - β) = sin(-0.5055π)
sin(α - β) = -sin(0.5055π)
sin(α - β) = -sin(90.99)
sin(α - β) ≈ -0.116
