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3 years ago

Which compound would have the lowest melting point?

Chemistry

1 answer:

IRINA_888 [86]3 years ago

7 0

The chemical with the lowest point is helium

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In which situation is no work considered to be done by a force?

Elena L [17]

Work is done when the application of a force causes movement of an object in the direction of the force.
If there is no movement of the object or the object does not move in the direction of the force then work is not done.

6 0

3 years ago

The most common oxygen is an atom with 8 protons and 8 neutrons what is the mass of this isotope

Angelina_Jolie [31]

Answer:

16 i think

Explanation:

7 0

3 years ago

The molecular weight of an organic compound was determined by measuring the freezing point depression of a benzene solution. A 0

Rudiy27

<u>Answer:</u> The molar mass of the sample is 120.6 g/mol

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$\Delta T_f$ = depression in freezing point = 0.42°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point elevation constant = 5.065°C/m

$m_{solute}$ = Given mass of solute (sample) = 0.500 g

$M_{solute}$ = Molar mass of solute (sample) = ? g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 50.0 g

Putting values in above equation, we get:

$0.42^oC=1\times 5.065^oC/m\times \frac{0.500\times 1000}{M_{solute}\times 50.0}\\\\M_{solute}=\frac{1\times 5.065\times 0.500\times 1000}{50.0\times 0.42}=120.6g/mol$

Hence, the molar mass of the sample is 120.6 g/mol

5 0

4 years ago

What is the correct answer and why?

MariettaO [177]

A) number of neutrons in the nucleus... all isotopes of an element contain the same number of protons which is equal to that elements atomic number...
hope this helps!

7 0

3 years ago

A stream of air (21 mole% o2, the rest n2) flowing at a rate of 10.0 kg/h is mixed with a stream of co2. the co2 enters the mixe

Zepler [3.9K]

Molecular weight of air = 29 g/mole, moles of air entering = 5/29 kgmoles/hr= 0.1724 kg moles/hr
Moles of N2= 0.21*0.1724=0.036 kg moles/hr, moles of N2= 0.79*0.1724= 0.1362 kgmoles/hr
Moles of CO2 can be calculated from gas law equation, n= PV/RT
V= 25 m3/hr= 25* 1000 L/hr, P= 2 bar = 2*0.9869 atm,=1.9738 atm R= 0.0821 L.atm/mole.K T= 100 deg.c =100+?273.15= 373.15K
n= number of moles of CO2= 1.9738*25*1000/ (0.0821*373.15) =1611 moles/hr= 1.611 kg moles/hr
total moles of mixture = 0.1724 +1.611 =1.7834 kg moles/hr
Moles % CO2 in the mixed stram = 100*1.611/1.7834 = 90.33%
Answer is 90.33%

6 0

3 years ago