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Hunter-Best [27]
3 years ago
12

Saltwater _____. has a pH of 10 is mostly used for irrigation and farming can be desalinized and used for drinking is mostly fou

nd in glaciers, ice caps, and aquifers
Chemistry
1 answer:
tiny-mole [99]3 years ago
8 0
I think the best statement to fill the blank is that "can be desalinized and used for drinking". The said statement seems the most appropriate one because the pH of saltwater is not 10 but approximately between 7.6 to 8.4. Also, saltwater is not found in glaciers, ice caps and aquifers instead it is freshwater.
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In the electron cloud model of the atom, an orbital is defined as the most probable(1) charge of an electron
Galina-37 [17]

The correct answer would be 3.) Location of an electron
3 0
3 years ago
what is the correct conversion factor by which to multiply to convert moles of nitrogen to moles of ammonium nitrate (NH4NO3)
Ostrovityanka [42]

Answer:

0.5

Explanation:

1 mole of ammonium nitrate contains 2 moles of nirogen

1 mole of nitrogen converts to 0.5  moles of ammonium nitrate

the conversation factor is 0.5

6 0
3 years ago
Read 2 more answers
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
Answer the following questions that relate to electrochemical reactions. (a) Under standard conditions at 25˚C, Zn(s) reacts wit
Elanso [62]

Answer:

0.48 V

Explanation:

Zn(s) ------------> Zn^2+(aq) + 2e. Oxidation half equation (-0.76V)

Co^2+(aq) + 2e-----------> Co(s). Reduction half equation (-0.28)

Zn(s) + Co^2+(aq) -------------> Zn^2+(aq) + Co(s) overall redox equation

Zinc is the anode while cobalt is the cathode.

E°cell= E°cathode - E°anode

E°cell= -0.28-(-0.76)= 0.48 V

7 0
4 years ago
Read 2 more answers
If a sample containing 2.00 mL of nitroglycerin (density=1.592g/mL) is detonated, how many total moles of gas are produced?
fgiga [73]

The overall balanced chemical reaction for this is:

Detonation of Nirtoglycerin <span>
4 C3H5N3O9 --> 12 CO2 + 6 N2 + O2 + 10 H2O </span>

 

Therefore:

2.00 mL x 1.592 g/mL = 3.184 g <span>
3.184 g / 227.1 /mol = 0.0140 mol nitroglycerin 
4 moles --> 12 + 6 + 1 + 10 = 29 moles of gas 
<span>0.0140 mol x (29/4) = 0.1017 moles of gases or (0.102 mol) </span></span>

6 0
3 years ago
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