Answer:
i) SF = 0.83
ii) 10 psi
iii) 3.16 psi
iv) 0.0083
Explanation:
Constant load = 1000 Psi
mean resistance = 1200 psi
Probability of failure = 1.9 * 10^-3
<u>Determine </u>
<u>i) Safety factor </u>
S.F = 1 / (mean load / load design ) = 1 / ( 1200 / 1000 ) = 0.83
<u>ii) Standard deviation </u>
1.9 X 10^-3 = e ( -1/2 ( μ / б) ^3 / (2.5 * 6 )
0.004756 = e^- 20000 / б^3
hence std = 10 psi
<u>iii) Variance </u>
=
= 3.16 psi
<u>iv) coefficient of variation </u>
Cv = std / mean resistance
= 10 / 1200 = 0.0083
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Answer:
∆S1 = 0.5166kJ/K
∆S2 = 0.51826kJ/K
Explanation:
Check attachment for solution
Answer:
Explanation:
Given



From Clausius inequality
=Reversible cycle
=Irreversible cycle
=Impossible
(a)For 
Rejected heat 


thus it is Impossible cycle
(b)



Possible
(c)Carnot cycle




and maximum Work is obtained for reversible cycle when operate between same temperature limits

Thus it is possible
Known :
Q = 300 L/s = 0.3 m³/s
D1 = 350 mm = 0.35 m
D2 = 700 mm = 0.7 m
g = 9.81 m/s²
Solution :
A1 = πD1² / 4 = π(0.35²) / 4 = 0.096 m²
A2 = πD2² / 4 = π(0.7²) / 4 = 0.385 m²
hL = (kL / 2g) • (U1² - U2²)
hL = (kL / 2g) • Q² (1/A1² - 1/A2²)
hL = (1 / 2(9.81)) • (0.3²) • (1/(0.096²) - 1/(0.385²))
hL = 0.467 m