Answer: Technical sales engineer
Explanation:
An analysis engineer makes use of data and other technical information in order for him or her to be able to analyze a project plan, and provide necessary solutions.
Technical sales engineers gives their clients the needed support and sales advice for their business to thrive. Technical sales engineers helps their clients in giving technical advices, answering queries, as well as introducing new products.
Design engineers are the engineers that study, and develop ideas that will be used for new products. Sometimes, they also modify systems used in production so that organizational performance can be improved.
Inspection engineers are the engineers that looks at infrastructures and identify the problems affecting them e.g oil pipelines, roads, bridges, etc so that accidents will be prevented.
Consulting engineer is an engineer that deals with the planning, and infrastructures. Their work benefits the society as a whole.
Based on the above explanation, the answer is technical sales engineer.
Answer:
The availability of system will be 0.9
Explanation:
We have given mean time of failure = 900 hours
Mean time [to repair = 100 hour
We have to find availability of system
Availability of system is given by 
So availability of system 
So the availability of system will be 0.9
Answer:
see explaination
Explanation:
import java.util.InputMismatchException;
import java.util.Scanner;
public class calculate {
static float a=0,b=0;
double cal()
{
if(a==0||b==0)
{
System.out.println("no values found in a or b");
start();
}
double x=(a*a)+(b*b);
double h=Math.sqrt(x);
a=0;
b=0;
return h;
}
float enter()
{
float val=0;
try
{
System.out.println("Enter side");
Scanner sc1 = new Scanner(System.in);
val = sc1.nextFloat();
return val;
}
catch(InputMismatchException e)
{
System.out.println("Enter correct value");
}
return val;
}
void start()
{
calculate c=new calculate();
while(true)
{
System.out.println("Enter Command");
Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
switch(input)
{
case "A":
a=c.enter();
break;
case "B":
b=c.enter();
break;
case "C":
double res=c.cal();
System.out.println("Hypotenuse is : "+res);
break;
case "Q":
System.exit(0);
default:System.out.println("wrong command");
}
}
}
public static void main(String[] args) {
calculate c=new calculate();
c.start();
}
}
Answer:
False I'm pretty sure sorry If its wrong
Answer:
final temperature is 424.8 K
so correct option is e 424.8 K
Explanation:
given data
pressure p1 = 1 bar
pressure p2 = 5 bar
index k = 1.3
temperature t1 = 20°C = 293 k
to find out
final temperature t2
solution
we have given compression is reversible and has an index k
so we can say temperature is
![\frac{t2}{t1}= [\frac{p2}{p1}]^{\frac{k-1}{k} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt2%7D%7Bt1%7D%3D%20%5B%5Cfrac%7Bp2%7D%7Bp1%7D%5D%5E%7B%5Cfrac%7Bk-1%7D%7Bk%7D%20%7D)
...........1
put here all these value and we get t2
![\frac{t2}{293}= [\frac{5}{1}]^{\frac{1.3-1}{1.3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bt2%7D%7B293%7D%3D%20%5B%5Cfrac%7B5%7D%7B1%7D%5D%5E%7B%5Cfrac%7B1.3-1%7D%7B1.3%7D%20%7D)
t2 = 424.8
final temperature is 424.8 K
so correct option is e
