Answer:
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Explanation:
For steel bolt
Stress = 210 MPa or 210 N/mm2
Pressure = Stress* Area
Pbolt = 210 N/mm2 * 16^2 *(pi)/4
Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6 N
For Brass spacer
Pressure = 42201.6 N
Area of Brass spacer = Pressure/Stress
Area of Brass spacer = 42201.6 N/145 N/mm^2 = 291.044 mm^2
Area of Brass spacer = (pi) (d^2 - 16^2)/4 = 291.044 mm^2
d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758
d^2 = 370.758 + 16^2
d^2 = 626.758
d = 25.03 mm
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Answer:
The split is given by including spaces in both tabs
Explanation:
The bracket notation can be used to indicate the split. Here is an example:
String [ ] parts = s. split ( "[/]")
Answer
Statically determinate beams are those beams in which the unknown reaction forces are equal or less than the equilibrium equation.
As shown in figure 1 in which reaction forces are 3 and we have 3 equilibrium equation so beam is determinate.
Statically indeterminate beams are those beams in which unknown reaction force are more than the equilibrium equation.
As shown in figure 2 in which reaction forces are 6 and we have 3 equilibrium equation so beam is indeterminate.
Explanation:
D the answer is D and anyone can answer this Question
Answer:
# string_contains function is defined with input_string
# as arguments
def string_contains(input_string):
# if-statement that check if letter z is in input_string
if 'z' in input_string:
# it print"has the letter z" if it has z
print("has the letter z")
else:
# else it print "not worthwhile"
print("not worthwhile")
# string_contains function is called
string_contains("The animal is zebra")
string_contains("learning is fun")
Explanation:
The code is written in Python and well commented.
Image of the output when the function is called is attached.