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Cloud [144]
3 years ago
8

A map. The map shows the physical features of the Fertile Crescent. The Fertile Crescent begins at the northern end of the Persi

an Gulf, continues north and west following the Euphrates River and Tigris River, and narrows down the western coast of the Syrian Desert ending in Upper Egypt. The empires of Mesopotamia, Akkad, Babylonia, and Sumer are within the Fertile Crescent. East of Sumer are the Zagros Mountains. Use the drop-down menus to identify the physical features on the map. The area south of the Fertile Crescent is the . The body of water that crosses the Fertile Crescent is the . One body of water that borders the Fertile Crescent is the . One physical feature located east of the Fertile Crescent is the .
Chemistry
2 answers:
boyakko [2]3 years ago
7 0

Answer:

It’s syrian desert, euphrates river, persian gulf and zagros mountains

Explanation:

i got it right

lys-0071 [83]3 years ago
5 0

Answer:

The Persian Gulf and the Tigris and Euphrates

Explanation:

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A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m
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311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( q_{\ lost} )= heat absorbed by the less hotter  sample( q_{\ gain} )

The relationship between heat (q), mass (m) and temperature (t) is q = mc\Delta t

where c is specific heat capacity, \Delta t temperature change.

\Delta t = t_{\ final} - t_{\ initial}

equating both heat emitted and absorb

-q_{\ lost} = q_{\ gain}

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * (t_{final} - 330) = 30 *  (t_{final} - 280)

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80t_{final} = 16500+8400

80t_{final} = 24900

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