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3 years ago

5

I need heelp plzzzzz can anyone heelp mee

2 answers:

yarga [219]3 years ago

7 0

C) 1 is the best option because all of the other options would be to many. But 1 is the closest to 1.04.

sveticcg [70]3 years ago

4 0

Answer:

e) 1.04

Explanation:

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You plug in an extension cord and have to be very careful around the electrical outlet. However, you can handle the extension co

a_sh-v [17]

I believe that the best statement which explains why you can do this is C. <span>The extension cord is made of copper wire, which is a good conductor of electricity; however, it is covered with plastic, an insulator, which does not allow the electrical current to flow to you.
Copper is known to be one of the best conductors of electricity, and plastic can shield you from shock.

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3 0

3 years ago

Read 2 more answers

What is the speed of a wave frequency of 300hz and a wavelength of 25M

tia_tia [17]

Answer:

7500 m/s

Explanation:

We can use the equation velocity of a wave equals wavelength times frequency. Therefore, v = wavelength*f = (25 m)(300 Hz) = m/s7,500

8 0

3 years ago

One mole of an ideal gas does 3000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and

taurus [48]

Answer:

(a) Initial volume will be 7.62 L

(b) Final temperature will be 303.85 K

Explanation:

We have given one mole of ideal gas done 3000 J

So work done W = 3000 J

Let initial volume is $V_1$ and initial pressure $P_1=1atm$ ( As pressure is constant )

Final volume $V_2=25L$ = 0.025 $m^3$

Number of moles n = 1

(B) From ideal gas of equation we know that $PV=nRT$

So $1.01\times 10^5\times0.025=1\times 8.31\times T$

T = 303.85 Kelvin

(B) For isothermal process work done is equal to

$W=nRTln\frac{V_2}{V_1}$

$3000=1\times 8.314\times 303.85\times ln\frac{0.025}{V_1}$

$ln\frac{0.025}{V_1}=1.1881$

$\frac{0.025}{V_1}=3.2808$

$V_2=0.00846m^3=7.62L$

So initial volume will be 7.62 L

5 0

3 years ago

The switch has been open for a long time before it is closed at t = 0. what is ustored, the total stored energy in the circuit e

Ivahew [28]

0. No time comparison.

5 0

3 years ago

The specific heat of water is 4.2 J/g • °C. How much heat is required to raise the temperature of 100 g of water by 5°C? *

Svetach [21]

Answer:

2100 J

Explanation:

The heat required to increase the temperature of a substance is given by

$Q=mC\Delta T$

where

m is the mass of the substance

C is its specific heat capacity

$\Delta T$ is its change in temperature

For the water in this problem, we have:

m = 100 g is its mass

C = 4.2 J/g • °C is the specific heat capacity

$\Delta T=5^{\circ}C$ is the increase in temperature

So, the amount of heat needed is:

$Q=(100)(4.2)(5)=2100 J$

7 0

3 years ago