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shtirl [24]
4 years ago
13

Todd has 2 frogs. This is 1/3 the number of frogs that Heather has. How many frogs does Heather have?

Mathematics
2 answers:
spin [16.1K]4 years ago
8 0
Heather has 6 frogs because 1/3 of that is 2 and todd has 2 frogs
Murljashka [212]4 years ago
5 0
2=1/3H
H=2*3
Heather has 6 frogs
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A group of 4 friends go out for dinner and the total cost of the dinner is $200. They use a $40 coupon before splitting the bill
lorasvet [3.4K]

Answer:

$40.00

Step-by-step explanation:

the total is 200 so then u subtract the $40 from the coupon which will leave u with 160. Since there is 4 people 160/4 equals 40. Therefore your answer is each person pays $40.00

6 0
3 years ago
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In circle A shown below, m is 67° and m is 74°. <br> What is m∡FDE?
deff fn [24]
Use this theorem: in a circle, the measure of an angle formed by two chords that intersect inside the circle is half the sum of the arcs formed by the chords.

In this case the sum of the arcs formed by the chords is 67° + 74° = 141 °, then the half is 141° / 2 = 70.5°.

Answer: 70.5°
8 0
3 years ago
Good morning babe I'm sorry for the late reply with quote from the people that have not heard back yet to see you doing anything
WARRIOR [948]

what do you need help with?

8 0
3 years ago
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Find the root of each of the following equation x+8=24​
kupik [55]

Answer:

4

Step-by-step explanation:

If you mean root of x, 24-8=16

square root of 16=4

4 0
3 years ago
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

4x=3x

\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

4 0
3 years ago
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