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frozen [14]
3 years ago
13

Reuben drove 260 miles using 12 gallons of gas. At this rate, how many gallons of gas would he need to drive miles

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
8 0

Answer:

286 miles / x gallons = 15miles per gallon.

286/15 = x = approximately 19.07 gallons.

Step-by-step explanation:

sammy [17]3 years ago
3 0
Reuben would need 13.2 gallons of gas to drive 286 miles.
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A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
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Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

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