Answer:
6 moles
Explanation:
From the equation you can see that twice as many HCL moles are used as H2 produced
2 x 3 = 6 moles of HCL required
<u>Answer:</u> The final pressure of the gas is 9.41 atm
<u>Explanation:</u>
To calculate the pressure of the gas, we use the equation given by ideal gas equation:
where,
P = pressure of the gas = ?
V = Volume of gas = 
(Conversion factor: 
)
n = Number of moles = 0.01 mol
R = Gas constant = 
T = temperature of the gas = ![300^oC=[300+273]K=573K](https://tex.z-dn.net/?f=300%5EoC%3D%5B300%2B273%5DK%3D573K)
Putting values in above equation, we get:
Hence, the final pressure of the gas is 9.41 atm
Answer:
pH 8.89
Explanation:
English Translation
If the MgCl₂ solution of 0.2 M has its pH raised by adding NH₄OH, the precipitate will begin to form at a pH of approximately.
Given the solubility product (Ksp) of Mg(OH)₂ = 1.2 x 10⁻¹¹
Assuming all of the salts involved all ionize completely
MgCl₂ ionizes to give Mg²⁺ and Cl⁻
MgCl₂ ⇌ Mg²⁺ + 2Cl⁻
1 mole of MgCl₂ gives 1 moles of Mg²⁺
Since the concentration of Mg²⁺ is the same as that of MgCl₂ = 0.2 M
Mg(OH)₂ is formed from 1 stoichiometric mole of Mg²⁺ and 2 stoichiometric moles of OH⁻
Ksp Mg(OH)₂ = [Mg²⁺][OH⁻]²
(1.2 x 10⁻¹¹) = 0.2 × [OH⁻]²
[OH⁻]² = (6×10⁻¹¹)
[OH⁻] = √(6×10⁻¹¹)
[OH⁻] = 0.000007746 M
p(OH) = - log [OH⁻] = - log (0.000007746)
pOH = 5.11
pH + pOH = 14
pH = 14 - pOH = 14 - 5.11 = 8.89
Hope this Helps!!!
Answer:
It is like an arch because it bends horizontal just like we do and the legs of the arch support the stone like our feet and legs support the weight of us.
Explanation:
There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
= 25/1000 liter
= 0.025 liter
V2 = 18 ml
= 18/1000 liter
= 0.018 liter
M2 = 1.0 M
M1 = ?
Then
M1V1 = M2V2
M1 = M2V2/V1
= (1 * 0.018)/0.025
= 0.72 M
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
